Displacement vector that is 8 im magnitude
Answer:
t = 2.38 [s]
Explanation:
To solve this problem we must use the following equation of kinematics. We must clarify that both the acceleration and the initial velocity were taken as positive, since the velocity of the movement coincides with the direction of the acceleration.
where:
x - Xo = distance = 47 [m]
Vo = initial velocity = 8 [m/s]
a = gravity acceleration = 9.81 [m/s²]
t = time [s]
Now replacing these values in the equation:
47 = 8*t + 0.5*9.81*t²
47 = 8t + 4.905t²
47 = 4.905*t(1.63 + t)
9.58 = t*(1.63 + t) solving this equation (cuadratic)
we found that t = 2.38 [s]
Answer: D) Earthquake
<em>I hope this helps, and Happy Holidays! :)</em>
Explanation:
Initial speed of the rocket, u = 0
Acceleration of the rocket,
Time taken, t = 3.39 s
Let v is the final velocity of the rocket when it runs out of fuels. Using the equation of kinematics as :
Let x is the initial position of the rocket. Using third equation of kinematics as :
Let is the position at the maximum height. Again using equation of motion as :
Now and v and u will interchange
x = 524.14 meters
Hence, this is the required solution.