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xz_007 [3.2K]
4 years ago
6

Which is the best way to solve the equation?​

Mathematics
1 answer:
stiks02 [169]4 years ago
5 0

Option D:

Square both sides of the equation is the best way to solve the equation.

Solution:

Given equation:

\sqrt{x}=k

To find which is the best way to solve the equation.

Option A: Multiply both sides of the equation by k.

\sqrt{x}=k

k\sqrt{x}=k^2

In this method, we are not obtain x value.

It is not true.

Option B: Divide both sides of the equation by k.

$\frac{\sqrt{x}}{k} =\frac{k}{k}

$\frac{\sqrt{x}}{k} =1

In this method, we are not obtain x value.

It is not true.

Option C: Take the square root of both sides of the equation.

\sqrt{\sqrt{x}}=\sqrt{k}

x^{\frac{1}{4} }=\sqrt{k}

In this method, we are not obtain x value.

It is not true.

Option D: Square both sides of the equation.

(\sqrt{x})^2=k^2

Square and square root get canceled.

x=k^2

We obtain x value.

It is true.

Therefore square both sides of the equation is the best way to solve the equation.

Option D is the correct answer.

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A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. ​a) E
polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) \alpha =1-0.98=0.02

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq  p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and z_{\alpha/2} is the z-value that let a probability of \alpha/2 on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, \alpha by 0.02 and z_{\alpha/2} by 2.33

Where p' and \alpha are calculated as:

p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02

So, replacing the values we get:

0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq  p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence 1-\alpha is equal to 98%

It means the the level of significance \alpha is:

\alpha =1-0.98=0.02

4 0
3 years ago
A log raft is moving downstream at a speed of 3 km/h. To insure that there are no river jams a supervisor travels along the raft
skad [1K]

Answer:

2000 meters

Step-by-step explanation:

When the motorboat is moving downstream, its speed relative to the ground is 18 km/h, so its speed relative to the raft is 15 km/h.

When the motorboat is moving upstream, its speed relative to the ground is 12 km/h, so its speed relative to the raft is again 15 km/h.

Converted to m/min, the relative speed is:

15 km/h × (1000 m/km) × (1 h / 60 min) = 250 m/min

It takes the motorboat 16 minutes to travel to the front of the raft and back.  Since the speed is the same in both directions, the motorboat takes 8 minutes to travel the length of the raft.

So the length of the raft is 250×8 = 2000 meters.

8 0
3 years ago
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