All categories

3 years ago

Can someone tell me if this is right thanks

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

7 0

bearing in mind that an absolute value expression is in effect a piece-wise expression, because it has a ± version.

$\bf 3|x|+7=28\implies 3|x|=21\implies |x|=\cfrac{21}{3}\implies |x|=7\implies \begin{cases} +(x)=7\\ -(x)=7 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ +(x)=7\implies \boxed{x=7}~\hfill -x=7\implies \boxed{x=-7}$

saveliy_v [14]3 years ago

3 0

Yeah because 31x1+7-7=28-7=21

You might be interested in

The final scores of students in a graduate course are distributed normally with a mean of 72 and a standard deviation of 5. What

Tcecarenko [31]

Answer:

0.8041

Step-by-step explanation:

We know that

μ=72 and σ=5

and P(65<X<78)

We can determine the Z value as (X-μ)/σ

P( 65<X<78 )=P( 65-72< X-μ<78-72)

$P((65-72)/5$

$P(65$

To fine the Z values:

$P (-1.4$

From the standard normal tables:

$P (Z$

to find P ( Z<-1.4)

$P ( Z$

From the standard normal tables:

$P ( Z$

Therefore

$P(-1.4$

$P (65$

8 0

3 years ago

I’ll give brainliest to the person who answers this right. Please help!!

Charra [1.4K]

Answer:

3.43

Step-by-step explanation:

To do this you would first find the area of the square which is 16. Then you would find the area of the 2 semicircle or just on whole circle. We are just going to use the formula for a whole circle since there are 2 semicircles. The formula to find a circle is pi times r^2 so we are going to put that into a calculator so we would do pi times 2 (radius of circle)^2 which is 12.57 and we would subtract 16 by 12.57 which is 3.43

5 0

2 years ago

Read 2 more answers

Jenny had $17 more than Susan, and together they had enough money to buy a game for $93 and to have a pizza for $6. How much mon

storchak [24]

<h2><em>Jenny had 58 and Susan had 41.</em></h2>

8 0

3 years ago

Read 2 more answers

You are riding on a road at 5mph and your friennd in the same direction at 3mph with a head start of 1/2 mile. how long will it

VashaNatasha [74]

You will catch up in 15 minutes

4 0

3 years ago

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 3x2 − 2x + 1, [0, 2] Yes, it do

expeople1 [14]

Answer:

Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable

Step-by-step explanation:

We are given the Function

f(x) = $3x^2 -2x +1$

The two basic hypothesis of the mean valued theorem are

The function should be continuous in [0,2]

The function should be differentiable in (1,2)

upon checking the condition stated above on the given function

f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph

also the f(x) is differentiable in (0,2)

f'(x) = 6x - 2

Now the function satisfies both the conditions

so applying MVT

6x-2 = f(2) - f(0) / 2-0

6x-2 = 9 - 1 /2

6x-2 = 4

6x=6

x=1

so this is the tangent line for this given function.

4 0

2 years ago