345mi +3hr+ 15 mph the slowest car traveled
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The complete question in the attached figure
we know that
m angle bad =75°
remember that on parallelogram
(∠A + ∠<span>B) = 180°
[Since, sum of the interior angles on the same side of the transversal is 180°]
therefore
</span>∠B=180°-∠A=180°-75°=105°
∠B=105°
<span>Similarly
∠B + ∠C = 180°
∠C + ∠D = 180°
and ∠D + ∠A = 180°</span>
<span>Thus, the sum of any two adjacent angles of a parallelogram is 180°.
</span>
m angle bcd=∠C=180-∠B=180°-105°=75°
the answer is m angle bcd=75°
we know that
m angle bad =75°
remember that on parallelogram
(∠A + ∠<span>B) = 180°
[Since, sum of the interior angles on the same side of the transversal is 180°]
therefore
</span>∠B=180°-∠A=180°-75°=105°
∠B=105°
<span>Similarly
∠B + ∠C = 180°
∠C + ∠D = 180°
and ∠D + ∠A = 180°</span>
<span>Thus, the sum of any two adjacent angles of a parallelogram is 180°.
</span>
m angle bcd=∠C=180-∠B=180°-105°=75°
the answer is m angle bcd=75°