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4 years ago

What is 4 square root of 81 to the fifth power in exponential form

Mathematics

1 answer:

creativ13 [48]4 years ago

5 0

Answer:

B is the answer.

Step-by-step explanation:

$x^{\frac{m}{n} } = \sqrt[n]{x^{m} }$

$\sqrt[4]{81^{5} }$ = $81^{\frac{5}{4} }$

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kevin guesses randomly on 10 true or false questions, what is the probability that he gets at least 6 correct?

asambeis [7]

Answer: 6/10

Step-by-step explanation:

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2 years ago

(-4, -2),(-18,7) slope

Nuetrik [128]

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3 years ago

Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5

Bond [772]

Answer:

The solution to the equation system given is:

<u>x = 2</u>
<u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

2x + 3y = 1
3x + y = 5

Following Crammer's Rule, we have the matrix form:

$\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Now we solve using the determinants:

$x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2$

$y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1$

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

2x + 3y = 1
2(2) + 3(-1)= 1
4 - 3 = 1
1 = 1

And, with the second equation:

3x + y = 5
3(2) + (-1) = 5
6 - 1 = 5
5 = 5

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3 years ago

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choli [55]

Answer:

(-4 , 5)

Step-by-step explanation:

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