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2 years ago

Problem of the Week

Mathematics

1 answer:

Ierofanga [76]2 years ago

6 0

Answer:

CD is 6 cm and DE is 4 cm.

Step-by-step explanation:

Well it‘s the correct answer and I got it right so good luck out there bois!

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Someone help me with this question please

telo118 [61]

Answer:

b = square root of 44 or approx. 6.6

Step-by-step explanation:

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=%28sinx%5E%7B2%7D%20theta%29%5Cfrac%7Bx%7D%7By%7D%281%2Bcostheata%29" id="TexFormula1" title="

beks73 [17]

The result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

<h3>How to evaluate the expression?</h3>

The expression is given as:

$\sin^2(\theta) * (1 + \cos(\theta))$

Express $\sin^2(\theta)$ as $1 - \cos^2(\theta)$ .

So, we have:

$\sin^2(\theta) * (1 + \cos(\theta)) = (1- \cos^2(\theta)) * (1 + \cos(\theta))$

Open the bracket

$\sin^2(\theta) * (1 + \cos(\theta)) = 1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Express 1 as cos°(Ф)

$\sin^2(\theta) * (1 + \cos(\theta)) = cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Hence, the result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Read more about trigonometry expressions at:

brainly.com/question/8120556

#SPJ1

3 0

2 years ago

Please help ♡♡♡♡♡♡♡

lions [1.4K]

Step-by-step explanation:

$\angle AOB$ and $\angle BOC$ are linear pair angles.

$\therefore m\angle AOB + m\angle BOC = 180° \\ \therefore \: 3x + 124 \degree + 6x + 29 \degree = 180° \\ \therefore \: 9x + 153 \degree = 180° \\ \therefore \: 9x = 180° - 153 \degree \\ \therefore \: 9x = 27 \degree \\ \therefore \:x = \frac{27 \degree }{9} \\ \huge \pink{ \boxed{\therefore \:x =3 \degree }} \\ \\ \because \: m\angle BOC =6x + 29 \degree \\ \therefore \: m\angle BOC =6 \times3 \degree + 29 \degree \\ \therefore \: m\angle BOC = 18\degree + 29 \degree \\ \\ \huge \red{ \boxed{\therefore \: m\angle BOC = 47 \degree }}$

5 0

3 years ago

Please help me !!! anything helps

Nataly_w [17]

1 is 117 because 18x6.5 is 117

4 0

2 years ago

How far from an airport can an airplane fly and return in 8 hours, if it's outgoing speed is 160 km per hour and it's returning

PilotLPTM [1.2K]

<span>speed = distance/time
total time is 8 hours

outgoing speed is 160 km per hour,
so time = d/160

</span><span>returning speed is 240 km per hour,
so time = d/240

d/160 + d/240 = 8

3d/480 + 2d/480 = 8
5d/480 = 8
5d =480 (8)
5d = 3840
d=3840/5
d=768

answer: so the distance is 768 km</span>

4 0

2 years ago

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