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avanturin [10]
3 years ago
7

Find the sum of (8a + 2b - 4) and (3b - 5).

Mathematics
1 answer:
Vinil7 [7]3 years ago
7 0
8a + 2b - 4 + 3b - 5....combine like terms
8a + 5b - 9 <==
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What is 11x 26 and how do you solve it I reall To know.
Alika [10]

Answer:

286

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the range of the function: h(x)=x+1/x^2 - 7x+10
Elina [12.6K]

Answer:

  (-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)

Step-by-step explanation:

To make it easier to differentiate, we'll rewrite the function as ...

  h(x) = 2/(x-5) -1/(x-2)

Then the derivative is ...

  h'(x) = -2/(x-5)^2 +1/(x-2)^2

This will be zero when ...

  -2(x-2)^2 +(x-5)^2 = 0

  -2(x^2 -4x +4) +(x^2 -10x +25) = 0

  -x^2 -2x +17 = 0

  x^2 +2x +1 = 17 +1

  x +1 = ±√18 = ±3√2

  x = -1 ±3√2

The values of the function at these locations are ...

  h(-1-3√2) = -1 +(2/3)√2 ≈ -1.9428

  h(-1+3√2) = -1 -(2/3)√2 ≈ -0.0572

Then the range of h(x) is ...

  (-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)

5 0
3 years ago
Degrees kelvin K equals 273 plus degrees celsius C
luda_lava [24]
Try going with this method for that question ⬇⬇⬇⬇

k = 273 + C

5 0
3 years ago
What are the equations of the asymptotes of the rational function? Please explain. f(x)=<img src="https://tex.z-dn.net/?f=%5Cfra
tangare [24]

Answer:

vertical asymptote at x = 7

horizontal asymptote at y = 6

Step-by-step explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.


solve:  

x − 7 = 0 ⇒ x = 7  is the asymptote

Horizontal asymptotes occur as

lim ,f(x)→ c(a constant)

x → ± ∞

divide terms on numerator/denominator by x

f ( x ) = 5/ x +6= 5 /x + 6

x/ x − 7 /x      1 − 7/ x

as   x ± ∞ , f ( x ) → 0 +6

                1 − 0

⇒ y = 6  is the asymptote

graph{((5)/(x-7))+6 [-20, 20, -10, 10]}

3 0
3 years ago
Read 2 more answers
Write two expressions that are equivalent to 6(m + 2 + 7m)
Lynna [10]

Hey there!

You could \bold{distribute} "\bold{6}" into your terms

  • \bold{6(m+2+7m)}
  • \bold{6(m)=6m}
  • \bold{6(2)=12}
  • \bold{6(7m))=42m}

Next, you have to \bold{combine} your \bold{like-terms}

  1. \bold{6m(and)42m}
  2. \bold{12}
  • \bold{6m+42m=48m}
  • The "\bold{12}" stays the same since it doesn't have a like term in this equation
  • \bold{\rightarrow48m+12}

  • \boxed{\boxed{\bold{Answer:48m+12}}}\checkmark

Good luck on your assignment and enjoy your day!

~\bold{LoveYourselfFirst:)}

8 0
3 years ago
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