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Usimov [2.4K]
2 years ago
15

Help please .........

Mathematics
1 answer:
Paha777 [63]2 years ago
3 0
It is 40 which is Question A
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Round to the nearest whole number.<br> 432.846
Gelneren [198K]

Answer: 433 of course

432 is the whole number and 846 is the decimal,

the number closest to the whole number is 8

we can only round the number forward if the number is 5 or more than 5 (6,7,8,9)

so 432.856 rounds to 433

3 0
3 years ago
Read 2 more answers
Which polynomial function has zeros at 2, −4, and 1?
LuckyWell [14K]

Answer:

y = (x - 2)(x + 4)(x - 1)

Step-by-step explanation:

Given the zeros of a function say x = a and x = b, then

The factors are (x - a) and (x - b) and

y = (x - a)(x - b)

Given the zeros are x = 2, x = - 4, x = 1, then

the factors are (x - 2), (x - (- 4)) and (x - 1), that is

(x - 2), (x + 4), (x - 1) , thus

y = (x - 2)(x + 4)(x - 1)

6 0
2 years ago
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Nicole has 18 nickels n and dimes d. If the value of her coins is $1.45, how many of each coin does she
Sloan [31]

Answer:

19 nickel = .95

5 dimes = .50

Step-by-step explanation:

.95 + .50 = 1.45

3 0
3 years ago
A shopkeeper buys pens at the rate of ₹ 75 per 100. for how much should he sell each pen so as to make a gain of 15%? please hel
Lady bird [3.3K]

Answer:

He should sell each pen of Rs.0.8625 so as to make a gain of 15%

Step-by-step explanation:

  • Cost price of 100 pens = Rs.75
  • Cost price of 1 pen=\frac{75}{100} = 0.75
  • Gain%= 15%

Gain=15%X 0.75= 0.1125

SP = CP+Gain = 0.75+0.1125=0.8625

<u>So, He should sell each pen of Rs.0.8625 so as to make a gain of 15%</u>

#Learn more:

By selling 60 pens a shopkeeper gain the cp of 15 pen. If he bought 20 pens in rs36. Find the sp of one pen

brainly.in/question/15083989

https://brainly.in/question/7469007

3 0
3 years ago
If two polygons are SIMILAR, then the corresponding sides must be and the corresponding angles must be .
AveGali [126]

Answer:

Their sides must be in the same ratio and their angles must be equal.

Step-by-step explanation:

If two polygons are similar their sides must be in the same ratio and their angles must be equal.

e. g. -

If ABCDEF  and GHIJKL be the two polygons,

then,

\frac{AB}{GH} = \frac{BC}{HI} = \frac{CD}{IJ} = \frac {DE}{JK} = \frac {EF}{KL} = \frac{FA}{LG}

and,

∠ABC = ∠GHI ; ∠BCD =∠HIJ ; ∠CDE = ∠IJK ; ∠DEF =∠JKL ; ∠EFA =∠KLG;

∠FAB = ∠LGH .

5 0
3 years ago
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