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lianna [129]
3 years ago
14

How does solar altitude affect the length of the path of solar radiation through earth’s atmosphere?

Physics
1 answer:
Aleks [24]3 years ago
7 0
The angle of the Sun above the horizon, which is the solar altitude, influences the intensity ofsolar radiation received at Earth’s surface. At the place on Earth where the Sun is directlyoverhead, the local solar altitude has its maximum value of 90 degrees and solar rays are mostconcentrated. Whenever the Sun is positioned lower in the sky, solar radiation spreads over alarger area of Earth’s horizontal surface and thus is less intense. Solar radiation reaches theplanet essentially as parallel beams of uniform intensity. The nearly spherical Earth presents acurved surface to incoming solar radiation so that the noon solar altitude always varies withlatitude. The intensity of solar radiation actually striking Earth’s atmosphere is greatest at thelatitude where the noon Sun is in the zenith and decreases with distance north and south of thatlatitude. Decreasing solar altitude lengthens the path of the Sun’s rays through the atmosphere.As the path lengthens, the greater interaction of solar radiation with clouds, gases and aerosols<span>reduces its intensity</span>
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2. A student drives 7.8-km trip to school and averages a speed of
Alekssandra [29.7K]

Answer:

<em>The total time is: t=451.22 sec</em>

<em>The average speed is: V=34.57 m/s</em>

Explanation:

<u>Average speed</u>

The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

\displaystyle V=\frac{x}{t}

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.

We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is

x=2*7,800 m=15,600 m

The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

\displaystyle t1=\frac{x1}{v1}=\frac{7,800}{32.6}=239.26\ sec

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

\displaystyle t2=\frac{x2}{v2}=\frac{7,800}{36.8}=211.96\ sec

The total time is:

t=239.26\ sec+211.96\ sec=451.22\ sec

\boxed{t=451.22\ sec}

The average speed is:

\displaystyle V=\frac{15,600}{451.22}=34.57\ m/s

\boxed{\displaystyle V=34.57\ m/s}

6 0
3 years ago
PLEASE HELP!!
adelina 88 [10]

Answer:

D

Explanation:

Michael Faraday is probably best known for his discovery of electromagnetic induction, his contributions to electrical engineering and electrochemistry or due to the fact that he was responsible for introducing the concept of field in physics to describe electromagnetic interaction.

Electromagnetic or magnetic induction is the production of an electromotive force across an electrical conductor in a changing magnetic field.

Electrical engineering is an engineering discipline concerned with the study, design and application of equipment, devices and systems which use electricity, electronics, and electromagnetism.

Electrochemistry is the branch of physical chemistry that studies the relationship between electricity, as a measurable and quantitative phenomenon, and identifiable chemical change, with either electricity considered an outcome of a particular chemical change or vice versa.

6 0
2 years ago
In which of the following locations is an island arc likely to form?
inn [45]
<span>D. Along two converging oceanic plate boundaries</span>
7 0
3 years ago
Read 2 more answers
During takeoff, an airplane climbs with a speed of 130 m/s at an angle of 47 degrees above the horizontal. The speed and directi
Reptile [31]
130cos(47deg) = 88.6598 m/s
5 0
3 years ago
An engine does 10 J of work and exhausts 25 J of waste heat during each cycle.
noname [10]
The thermal efficiency is defined as follows

\eta = 1 - \frac{Q_{\text{out}}}{Q_\text{in}},

and the energy which is put into the system is

Q_{\text{in}} = W_\text{out} + Q_\text{out}.

In your case Q_\text{in} = 25 \text{ J},W_\text{out}=10 \text{ J}.

So Q_\text{out}=10 \text{ J} which gives an efficiency of

\eta = 1 - \frac{10 \text{ J}}{25 \text { J}} = 0.6 = 60 \%.





4 0
3 years ago
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