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BartSMP [9]
4 years ago
9

Static charges can be applied to neutral objects by friction, induction or conduction. What do all of these methods utilize to c

reate this charge?
Physics
2 answers:
olya-2409 [2.1K]4 years ago
6 0

Yes, the correct answer is electrons.

Oksana_A [137]4 years ago
3 0
The s<span>tatic charges that are applied to neutral objects by friction, induction or conduction main utilise the creation of electrons or electric charges. Electrons flow forming a current into a specific medium known as a conductor which is mainly due to a significant potential difference between two points.</span>
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A cheetah spotted a Gazelle. The cheetah runs at its top speed of 30 m/s for 15 seconds. Durning this time , a gazelle ,160 m fr
Xelga [282]

Answer:

A) 450 m

B) 27 m/s

C) 81 m, 243 m

D) Gazelle

Explanation:

A)

Since, the Cheetah is running at constant speed. Therefore, we use the equation:

s₁ = v₁t

where,

s₁ = distance covered by Cheetah = ?

v₁ = speed of Cheetah = 30 m/s

t = time taken = 15 s

Therefore,

s₁ = (30 m/s)(15 s)

<u>s₁ = 450 m</u>

<u></u>

B)

For final speed of Gazelle at the end of 6 s acceleration time we use 1st equation of motion:

Vf = Vi + at

where,

Vf = Final Speed of Gazelle at the end of 6 s = ?

Vi = Initial Speed of Gazelle = 0 m/s (Since, Gazelle is initially at rest)

t = time taken = 6 s

a = acceleration = 4.5 m/s²

Therefore,

Vf = (0 m/s) + (4.5 m/s²)(6 s)

<u>Vf = 27 m/s</u>

C)

For the distance covered by Gazelle at the end of 6 s acceleration time we use 2nd equation of motion:

s₂ = Vi t + (0.5)at²

where,

Vi = Initial Speed of Gazelle = 0 m/s (Since, Gazelle is initially at rest)

t = time taken = 6 s

a = acceleration = 4.5 m/s²

Therefore,

s₂ = (0 m/s)(6 s) + (0.5)(4.5 m/s²)(6 s)²

<u>s₂ = 81 m</u>

<u></u>

Now, for the distance covered during the last 9 s at constant velocity Vf, we use equation:

s₃ = Vf t

where,

s₃ = distance covered by Gazelle in last 9 s = ?

t = time = 9 s

Therefore:

s₃ = (27 m/s)(9 s)

<u>s₃ = 243 m</u>

D)

We know that, at the end of 15 seconds:

Distance covered by Cheetah = s₁ = 450 m

Distance Covered by Gazelle = s₂ + s₃ = 81 m + 243 m = 324 m

If we take the initial position of Cheetah as origin. Then the positions of both Gazelle and Cheetah with respect to origin will be:

Position of Cheetah = 450 m ahead of origin

Position of Gazelle = 324 m + 160 m = 484 m (Since, Gazelle was initially 160 m ahead of Cheetah)

<u>Hence, it is clear that Gazelle is ahead at the end of 15 s.</u>

5 0
3 years ago
Carrying Capacity is...?
Elodia [21]
Carrying capacity is the maximum amount of individuals a space can hold.
3 0
3 years ago
What is one way that an electric field is different from a magnetic field?
liubo4ka [24]

Answer with Explanation:

Electric field:It is the force per unit charge experienced by rest charge at any given point.

It is the area around the charge which is placed at rest.It is represented by E.

Mathematical formula:

E=\frac{F}{q}

Magnetic field:It is an area around moving charge in which moving charge particle experienced  magnetic force in that area.

Magnetic field is represented by B.

Mathematical formula :

F=qvBsin\theta

Where B=Magnetic field

q=Charge on particle

v=Velocity of particle

F=Magnetic force exert on particle

3 0
3 years ago
You have an empty 20 oz. soda bottle and you blow air over the opening to excite a fundamental standing wave. Now, you slice off
Tatiana [17]

Answer:

The frequency of the standing wave in the second case is higher than that in the first case

Explanation:

The frequency and wavelength of a wave are related.

The moment you sliced the bottle, you've reduced the wavelength of the bottle.

When wavelength decreases, frequency increases and vice versa.

So, When frequency increases in the second case, more wave crests pass a fixed point each second. That means the wavelength shortens. So, as frequency increases, wavelength decreases. The opposite is also true—as frequency decreases, wavelength increases.

3 0
4 years ago
Which of the following is NOT true of all the inner planets?
Artist 52 [7]

Hi there! :)

\large\boxed{\text{B. They are called gas giants.}}

In the solar system, we can categorize the planets as such:

Inner planets: Mercury, Venus, Earth, Mars

Outer planets: Jupiter, Saturn, Uranus, Neptune

The Inner planets are the only planets that consist of solid rock. They also do not have rings and have impact craters due to their early formation.

In comparison, all of the outer planets are primarily made up of gaseous material and contain rings.

Therefore, the correct choice is B.

7 0
3 years ago
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