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iVinArrow [24]
2 years ago
14

An object is placed perpendicular to the the principal axis of convex lens of focal length 8,the distance of the object from the

lens is 12cm .Find the position &nature of the image​
Physics
1 answer:
Digiron [165]2 years ago
7 0

Answer:

v = 24 cm and inverted image

Explanation:

Given that,

The focal length of the object, f = +8 cm

Object distance, u = -12 cm

We need to find the position &nature of the image​. Let v be the image distance. Using lens formula to find it :

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Put all the values,

\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{8}+\dfrac{1}{(-12)}\\\\v=24\ cm

So, the image distance from the lens is 24 cm.

Magnification,

m=\dfrac{v}{u}\\\\m=\dfrac{24}{-12}\\\\m=-2

The negative sign of magnification shows that the formed image is inverted.

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forsale [732]

Answer:

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Explanation:

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2 years ago
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liberstina [14]
Is this practically possible? How can a 100kg man fly? Hahaha
3 0
3 years ago
A single-turn circular loop of radius 6 cm is to produce a field at its center that will just cancel the earth's field of magnit
djverab [1.8K]

Answer:

The current is  I  = 6.68 \  A

Explanation:

From the question we are told that  

     The radius of the loop is  r =  6 \ cm  = 0.06 \ m

     The  earth's magnetic field is B_e =  0.7G=  0.7  G * \frac{1*10^{-4} T}{1 G}  = 0.7 *10^{-4} T

      The  number of turns is  N  =1

Generally the magnetic field generated by the current in the loop is mathematically represented as

        B  =  \frac{\mu_o  * N  *  I}{2 r }

Now for the earth's magnetic field to be canceled out the magnetic field generated by the loop must be equal to the magnetic field out the earth

         B  =  B_e

=>     B_e =  \frac{\mu_o  *  N  *  I  }{ 2 * r}

     Where  \mu is the permeability of free space with value  \mu _o  =   4\pi * 10^{-7} N/A^2

       0.7  *10^{-4}=  \frac{ 4\pi * 10^{-7}  * 1 * I}{2 * 0.06}

=>     I  =  \frac{2 *  0.06 *  0.7 *10^{-4}}{ 4\pi * 10^{-7} * 1}

       I  = 6.68 \  A

3 0
3 years ago
Mario rdoll a coin up a slope at 2 m/s. It travels 2.7 m, comes to a stop and rolls back down. What is the coin's acceleration?
leva [86]

The coin's acceleration is <u>0.37 m/s²</u>

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

<u>Calculation:-</u>

<u />

V² = U -2aS

a = U/2S

  = 2/2×2.7

   =  <u>0.37 m/s²</u>

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

Learn more about acceleration here:- brainly.com/question/29110429

#SPJ9

8 0
1 year ago
A cyclist is travelling eastwards at a velocity
VMariaS [17]

Answer:

0.02 m/s^2

Explanation:

change in velocity= 4.5m/s - 2.3m/s = 2.2 m/s

acceleration= change in velocity/change in time

acceleration= 2.2/120= 0.0183

= 0.02 (to 2 significant figures)

8 0
2 years ago
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