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3 years ago

If a person believes that dreams have hidden meaning he or she would agree with Freud's ideas about _ content

Physics

1 answer:

uysha [10]3 years ago

4 0

A.lucid because it makes more sense yo the answer how about you do it yourself

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How does cell transport make cellular respiration and photosynthesis work?

Aloiza [94]

Answer:

okjjjjkkkkjjjjhhjjikhggbvvh

4 0

3 years ago

A scaffold of mass 57 kg and length 6.5 m is supported in a horizontal position by a vertical cable at each end. A window washer

Mrac [35]

Explanation:

The given data is as follows.

$m_{1}$ = 57 kg, $m_{2}$ = 79 kg

$l_{1}$ = 6.5 m, $l_{2}$ = (6.5 - 1.9) m = 4.6 m

(a) The sum of torque ends about far end is as follows.

$m_{1}g \frac{l_{1}}{2} + m_{2}g \times l_{2} - T \times l_{1}$ = 0

$57 \times 9.81 \times \frac{6.5}{2} + 79 \times 9.81 \times (6.5 - 1.9) - T \times 6.5$ = 0

T = 828 N

Therefore, 828 N is the tension in the cable closer to the painter.

(b) Now, we will calculate the sum about close ends as follows.

$m_{1}g \frac{l_{1}}{2} + m_{2}g \times (1.9) - T \times l_{1}$

$57 \times 9.81 \times \frac{6.5}{2} + 79 \times 9.81 \times (1.9) - T \times 6.5$ = 0

T= 506 N

Therefore, 506 N is the tension in the cable further from the painter.

8 0

3 years ago

The temperatures (in degrees Fahrenheit) in Long Island recorded by the weather bureau over a week were 42, 49, 53, 55, 50, 47,

lora16 [44]

Answer:

Inter Quartile Range

Explanation:

Quartile is a positional statistical average, which divided the data into 4 equal halves.

Q1 (Lower Quartile) has 25% data below it, 75% above it. Q3 (Upper Quartile) has 75% data below it, 25% above it.

Interquartile range is the measure used to calculate how far the lower & upper quartiles are.

7 0

3 years ago

A Jeep accelerated at 2.2 m/s2 until after 18 seconds its displacement was 660 meters. Assuming the Jeep traveled in a straight

pogonyaev

Ok so we know:
The time (t) is 18seconds
The acceleration (a) is 2.2m/s2
The displacement (r) is 660

Using the equation
$r = ut + \frac{1}{2} a {t}^{2}$
With 'u' being the initial velocity we want, we get:
$660 = 18u + 356.4$
So:
$18u = 303.6$
So:
$u = 16.8666$
So the original/initial velocity was 16.8666 or 16.87 m/s

Hope this helped

5 0

3 years ago

Dos coches, uno de 1.000 kg que circula a 100 km/h, y otro de 1.200 kg que circula a 90

Kobotan [32]

The collision of car 2 is more violent (because more impulse is exerted)

Explanation:

The collision which is more violent is the one in which more impulse is exchanged.

The impulse exerted by each car on the wall is equal to the change in momentum of the car:

$I=m\Delta v$

where

m is the mass of the car

$\Delta v$ is the change in velocity

For the car 1,

m = 1000 kg

$\Delta v = -100 km/h \cdot \frac{1000 m/km}{3600 s/h}=-27.8 m/s$ (the sign is negative because the velocity of the car has changed from 100 km/h to 0 km/h)