All categories

3 years ago

1. For the three-part question that follows, provide your answer to each question in the given workspace. Identify

Mathematics

1 answer:

amm18123 years ago

6 0

Answer: a) 6 b) 11.53 c) the smallest number of significant digits is 4

Step-by-step explanation:

Complete the subtraction and addition (you can do this manually by lining up the decimal ... or... using a calculator)

2.784 - 3.00079 + 10.671 + 1.0798 = 11.5340

→ there are 6 digits in the answer

b & c)

2.784 has 4 significant digits

3.00079 has 6 significant digits

10.671 has 5 significant digits

1.0798 has 5 significant digits

→ the smallest number of significant digits is 4 so round the answer from part a to 4 significant digits: $\large\boxed{11.53}$

You might be interested in

What are the coordinates of this point? PLLEASS ANSWER IM GVING BRAINLIEST

mafiozo [28]

Answer:

Step-by-step explanation:

they are (-5,-4) hope this helped

7 0

3 years ago

Read 2 more answers

What is the minimum value of C = 7x + 8y, given the constraints: 2x + y ≥ 8, x + y ≥ 6, x ≥ 0, y ≥ 0. A. 32 B. 42 C. 46 D. 64

marshall27 [118]

Answer: The minimum value of C is 46.

Step-by-step explanation:

Since, Here, We have to find out Min C = 7x+8y

Given the constraints are $2x+y\geq 8$ -------(1)

$x+y \geq 6$ ------------- (2)

$x \geq 0$ , $y \geq 0$ -------- (3)

Since, For equation 1) x-intercept, (4, 0) and y-intercept (0,8)

And, $2\times 0+0\geq 8$ ⇒ $0\geq 8$ ( false)

Therefore the area of line 1) does not contain the origin.

For equation 2) x-intercept, (6, 0) and y-intercept (0,6)

And, $0+0\geq 6$ ⇒ $0\geq 6$ ( false)

Therefore the area of line 2) does not contain the origin.

Thus after plotting the constraints 1) 2) and 3) we get Open Shaded feasible region AEB ( Shown in below graph)

At A≡(0,8) , C= 64

At E≡(2,4), C= 46

At B≡(6,0), C= 42

Thus at B, C is minimum, And its minimum value = 42

5 0

3 years ago

Read 2 more answers

triangle LMN is similar to triangle FGH and LN/FH= 7/4. What is the ratio of the area of triangle LMN to the area of triangle FG

jeyben [28]

Answer:

Step-by-step explanation:

6 0

3 years ago

Write an equation in slope - intercept form passing through (2,5); slope 3 over 4

Ipatiy [6.2K]

We can use point slope form then convert to slope intercept

point slope
y-y1=m(x-x1)
m=slope
(x1,y1) is a givn point
point is (2,5)
slope is 3/4
y-5=3/4(x-2)
y-5=3/4x-6/2
add 5
y=3/4x-3+5
y=3/4x+2

4 0

3 years ago

Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are inches long, inches wide, and 8 inche

allochka39001 [22]

Answer:

- The number of small boxes that will fill the large box 1 = 64

- The number of small boxes that will fill the large box 2 = 56

Step-by-step explanation:

Complete Question

Items for a fundraiser are packaged in small boxes shaped like rectangular prisms that are 4.5 inches long, 4.5 inches wide, and 8 inches tall. To transport the items to an event, you want to know how many of the small boxes will fit in larger boxes. The larger boxes are available in two sizes. Large Box 1 is 24.25 inches long, 18 inches wide, and 24 inches tall. Large Box 2 is 20.5 inches long, 18.5 inches wide, and 24 inches tall. Both the small and large boxes must remain upright.

Solution

To know how many of the small boxes will fit in larger boxes, we need to obtain the volumes of the small box, large box 1 and large box 2.

Volume of a cuboid = L × W × H

For the small box,

Length = L = 4.5 inches

Width = W = 4.5 inches

Height = H = 8 inches

Volume of the small box = 4.5 × 4.5 × 8 = 162 in³

For large box 1,

Length = L = 24.25 inches

Width = W = 18 inches

Height = H = 24 inches

Volume of the large box 1 = 24.25 × 18 × 24 = 10,476 in³

For large box 2

Length = L = 20.5 inches

Width = W = 18.5 inches

Height = H = 24 inches

Volume of the large box 2 = 20.5 × 18.5 × 24 = 9,102 in³

The number of small boxes that'll fill the large box 1 = (10,476/162) = 64.667 = 64 small boxes (rounded down because the fraction cannot be forced into the large box 1.

The number of small boxes that will fill the large box 2 = (9,102/162) = 56.185 = 56 small boxes.

Hope this Helps!!!

7 0

3 years ago