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slamgirl [31]
2 years ago
15

Which of the following best describes the graph of this system of equations ? y=-2x+3 and 5y=-10x +15

Mathematics
1 answer:
ELEN [110]2 years ago
6 0

Remark

When talking about straight lines, D is never true. Never.

C is possible, but in this case not true. Read on.

B. Might be true but in this case it is not. The lines (to be parallel) have to have the same number in front of the x. These two lines do when you divide through by 5. But the y intercept has to be different. That is not so in this case. So B is incorrect.

A is your answer. If you divide through by 5 on the second one, you get the first one. They are identical.

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1/9

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(1/3)/3 = 1/9

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What is the least common multiple (LCM) of 7 and 8? will give brainlest if answered in 1 minute
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3 years ago
Find the work required to move an object in the force field F = e^x + y (1, 1, z) along the straight line from A(0, 0, 0) to B(-
DENIUS [597]

\vec F(x,y,z)=(e^x+y)(1,1,z)

is conservative if we can find a scalar function f such that \nabla f=\vec F. This would require

f_x=e^x+y

f_y=e^x+y

f_z=(e^x+y)z

Integrating both sides of the first equation wrt x gives

f(x,y,z)=e^x+xy+g(y,z)

Differentiating both sides of this wrt y gives

f_y=x+g_y=1\implies g_y=1-x\implies g(y,z)=y-xy+h(z)

but we assumed g was a function of y and z, independent of x. So there is no such f and \vec F is not conservative.

To find the work, first parameterize the path (call it C) by

\vec r(t)=(1-t)(0,0,0)+t(-4,5,-5)=(-4t,5t,-5t)

for 0\le t\le1. Then

\vec r'(t)=(-4,5,-5)

and the work is given by the line integral,

W=\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^1(e^{-4t}+5t,e^{-4t}+5t,-(e^{-4t}+5t)5t)\cdot(-4,5,-5)\,\mathrm dt

W=\displaystyle\int_0^1(125t^2+5t+(25t+1)e^{-4t})\,\mathrm dt=\boxed{\frac{2207}{48}-\frac{129}{16e^4}}

8 0
3 years ago
What is the area of the shaded area?
denis-greek [22]

First you want to find the area of the square, which would be 121. ( 11 x 11 )

Next you want to find the area of the circle, 78.54 ((pi)5^2)

Last, you want to subtract the area of the circle, from the area of the square that is shaded. Youre left with 42.46

Hope this helped

7 0
3 years ago
Read 2 more answers
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