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Ivahew [28]
3 years ago
12

Suppose player a scores the same number of runs for 8 seasons. Player b scores the same number of runs for 9 seasons. And player

c scores the same number of runs for 7 seasons. Which player scores the most player a 128 player b 113 and player c 142
Mathematics
1 answer:
diamong [38]3 years ago
4 0

The answer is letter A. 8 times 128=1024. 9 times 113=1017.7 times 142=994

<em>Klicker</em>

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8(-b+4)=<br> idk what the answer is please help
iren [92.7K]

Answer:

-8b+36 is the answer.

Step-by-step explanation:

=8(-b+4)

Opening brackets to simplify

=8✖️(-b)+8✖️4

=-8b+36 is the answer.

Hope this will help you :)

4 0
2 years ago
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Show me a graph of 6x + 5y &lt; 30
Fittoniya [83]
Here is a graph of <span>6x + 5y < 30</span>

7 0
3 years ago
In the monthly payment formula , what value would you put for r if the interest rate is 5.7%?
natulia [17]
In the monthly payment formula r is the percentage rate as a decimal.

To turn a percentage into a decimal, move the decimal point 2 places to the left.
 5.7% becomes 0.057

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3 years ago
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The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.
VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

\int\limits^2_{-1} {(f(x) - g(x))} \, dx

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx

We know that:

\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}

\int\limits^{}_{} {1} \, dx = x

\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}

Then our integral is:

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2}  + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3}  + (-1) - \frac{(-1)^2}{2}  )

The right side is equal to:

(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6

The bounded area is 5 + 5/6 square units.

3 0
2 years ago
A.(x-6, y-5). B.(x.-5, y-6) c.(x+5, y+6). D.(x+ 6, y+5)
Svet_ta [14]

Answer:

c. (x+5, y+6)

6 0
3 years ago
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