Suppose player a scores the same number of runs for 8 seasons. Player b scores the same number of runs for 9 seasons. And player
c scores the same number of runs for 7 seasons. Which player scores the most player a 128 player b 113 and player c 142
1 answer:
The answer is letter A. 8 times 128=1024. 9 times 113=1017.7 times 142=994
<em>Klicker</em>
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