Suppose player a scores the same number of runs for 8 seasons. Player b scores the same number of runs for 9 seasons. And player
c scores the same number of runs for 7 seasons. Which player scores the most player a 128 player b 113 and player c 142
1 answer:
The answer is letter A. 8 times 128=1024. 9 times 113=1017.7 times 142=994
<em>Klicker</em>
You might be interested in
Answer:
4/10, 6/15, 8/20, and 10/25
Step-by-step explanation:
Hope this helps. :)
Step-by-step explanation:
just guess and see
Answer:
listen picture is not clear
Answer:
6:9 ÷3
2:3
Step-by-step explanation:
1st write the ratio then simplify it with dividing with the Highest common factor on both sides
Answer:
x > -10
Step-by-step explanation:
2 + x > -8
x > -8 - 2
x > -10
