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luda_lava [24]
4 years ago
5

Solve the equation. Round the solution to the tenths place. 6.35t = 56.515 t =

Mathematics
1 answer:
Westkost [7]4 years ago
5 0

Answer:

t = 8.9

Step-by-step explanation:

6.35t = 56.515

56.515 / 6.35 = t

t = 8.9

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What is the next term in this geometric sequence?<br> 104, -52, 26, -13, ...
Yanka [14]

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The Answer is 6.5 because you are dividing by negative 2

Step-by-step explanation:

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3 years ago
Please help answer quickly!
bagirrra123 [75]

The fourth root of 16/81 is 2/3.

x^11/x^7 = x^4. The fourth root of x^4 is x.

y^8/y^6 = y^2 which remains inside the fourth root.

Answer: B.

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3 years ago
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What is an equation of the line that passes through the points (0, -4) and (-4, 6)?
Allushta [10]

I got this answer by first using the slope formula, which would result into \frac{0 - 4}{6 - 0}  \\for which the answer would be - ⅔ Then, the y-intercept could be found easily, since you already have it., which is (0,4). Since the format for all linear equations are y=mx+b , in which b means the y-intercept and m means the slope. So then, if you substitute - ⅔ for m and 4 for b , you would get

y =  -  \frac{2}{3} x + 4 \\

6 0
3 years ago
Sarah bought 18 boxes of 65 pens at $12 a box. She sold 378 of them at 3 for $1.00 and the rest at 4 for $1.00. Find her total p
KonstantinChe [14]

Answer:

$108

Step-by-step explanation:

1 box = $12

18 boxes = 12×18 = $216

Total = 18×65 = 1170 pens

Cost price, Cp = $216

3 = $1

378 = 378/3 = $126

1170-378= 792 pens remaining

4 = $1

792 = 792/4 = $198

Total selling price, sp = 126+198 = $324

Profit = Sp - Cp = 324 - 216 = $108

8 0
3 years ago
Find the equation of the tangent line at the point where the curve crosses itself. x = t^3-6t, y = t^2.
Sphinxa [80]

Here is the solution for this specific problem:

<span>Based from the graph, the curve will intersect itself at the y-axis, i.e. x = 0. </span><span>

</span><span>t^3 - 6t = 0 </span><span>
<span>t(t^2 - 6) = 0 </span>
<span>t = 0 or t = ± √6 </span>

<span>dx/dt = 3t^2 - 6 </span>
<span>dy/dt = 2t </span>

<span>dy/dx = 2t/(3t^2 - 6) </span>

<span>@ t = 0, dy/dx = 0. </span>
<span>x = 0, y = 0 </span>

<span>y = 0 </span>

<span>@ t = √6, dy/dx = 2√6/12 = √6/6 </span>
<span>x = 0, y = 6 </span>

<span>y - 6 = (√6/6) x </span>
<span>y = (√6/6)x + 6 </span>

<span>@ t = -√6, dy/dx = -2√6/12 = -√6/6 </span>
<span>x = 0, y = 6 </span>

<span>y - 6 = (-√6/6) x </span>
y = (-√6/6)x + 6</span>

So the equations of the tangent line at the point where the curve crosses itself are: <span>y = (√6/6)x + 6 and </span>y = (-√6/6)x + 6. I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

4 0
4 years ago
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