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Sav [38]
3 years ago
12

On the Moon, the acceleration due to the effect of gravity is only about 1/6 of that on Earth. An astronaut whose weight on Eart

h is 570 N travels to the lunar surface.
(a) What is his weight as measured on the Moon? (in Newtons)
(b) What is his mass on the Moon (in kg)?
Physics
1 answer:
Ulleksa [173]3 years ago
8 0
A = 94.22 Newtons

b = 58.16 kg

Gravity on the moon is 1.62 m/s^2
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Answer: A:The reproductive system produces hormones.

B:The reproductive system transports reproductive cells.

C:The reproductive system produces reproductive cells.

Explanation:

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A helicopter lifts a 72 kg astronaut 15 m vertically from the ocean by means of a cable. The acceleration of the astronaut is g/
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Answer:

a) F_H=776.952\ N

b) F_g=706.32\ N

c) v=5.4249\ m.s^{-1}

d) KE=1059.48\ J

Explanation:

Given:

  • mass of the astronaut, m=72\ kg
  • vertical displacement of the astronaut, h=15\ m
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a)

<u>Now the force of lift by the helicopter:</u>

Here the lift force is the resultant of the force of gravity being overcome by the force of helicopter.

F_H-F_g=m.a

where:

  • F_H= force by the helicopter
  • F_g= force of gravity

F_H=72\times 0.981+72\times9.81

F_H=776.952\ N

b)

The gravitational force on the astronaut:

F_g=m.g

F_g=72\times 9.81

F_g=706.32\ N

d)

Since the astronaut has been picked from an ocean we assume her initial velocity to be zero, u=0\ m.s^{-1}

using equation of motion:

v^2=u^2+2a.h

v^2=0^2+2\times 0.981\times 15

v=5.4249\ m.s^{-1}

c)

Hence the kinetic energy:

KE=\frac{1}{2} m.v^2

KE=0.5\times 72\times 5.4249^2

KE=1059.48\ J

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