I can help you do them for yourself :)
Answer:
(a) Magnetic moment will be ![17.212\times 10^{-4}A-m^2](https://tex.z-dn.net/?f=17.212%5Ctimes%2010%5E%7B-4%7DA-m%5E2)
(b) Torque will be ![6.024\times 10^{-4}N-m](https://tex.z-dn.net/?f=6.024%5Ctimes%2010%5E%7B-4%7DN-m)
Explanation:
We have given dimension of the rectangular 5.4 cm × 8.5 cm
So area of the rectangular coil ![A=5.4\times 8.5=45.9cm^2=45.9\times 10^{-4}m^2](https://tex.z-dn.net/?f=A%3D5.4%5Ctimes%208.5%3D45.9cm%5E2%3D45.9%5Ctimes%2010%5E%7B-4%7Dm%5E2)
Current is given as ![i=15mA=15\times 10^{-3}A](https://tex.z-dn.net/?f=i%3D15mA%3D15%5Ctimes%2010%5E%7B-3%7DA)
Number of turns N = 25
(A) We know that magnetic moment is given by ![magnetic\ moment=NiA=25\times 45.9\times 10^{-4}\times 15\times 10^{-3}=17.212\times 10^{-4}A-m^2](https://tex.z-dn.net/?f=magnetic%5C%20moment%3DNiA%3D25%5Ctimes%2045.9%5Ctimes%2010%5E%7B-4%7D%5Ctimes%2015%5Ctimes%2010%5E%7B-3%7D%3D17.212%5Ctimes%2010%5E%7B-4%7DA-m%5E2)
(b) Magnetic field is given as B = 0.350 T
We know that torque is given by ![\tau =BINA=0.350\times 15\times 10^{-3}\times 25\times 45.9\times 10^{-4}=6.024\times 10^{-4}N-m](https://tex.z-dn.net/?f=%5Ctau%20%3DBINA%3D0.350%5Ctimes%2015%5Ctimes%2010%5E%7B-3%7D%5Ctimes%2025%5Ctimes%2045.9%5Ctimes%2010%5E%7B-4%7D%3D6.024%5Ctimes%2010%5E%7B-4%7DN-m)
<u>Momentum</u>
- a vector quantity; has both magnitude and direction
- has the same direction as object's velocity
- can be represented by components x & y.
Find linebacker momentum given m₁ = 120kg, v₁ = 8.6 m/s north
P₁ = m₁v₁
P₁ = (120)(8.6)
[ P₁ = 1032 kg·m/s ] = y-component, linebacker momentum
Find halfback momentum given m₂ = 75kg, v₂ = 7.4 m/s east
P₂ = m₂v₂
P₂ = (75)(7.4)
[ P₂ = 555 kg·m/s ] = x-component, halfback momentum
Find total momentum using x and y components.
P = √(P₁)² + (P₂)²
P = √(1032)² + (555)²
[[ P = 1171.77 kg·m/s ]] = magnitude
!! Finally, to find the magnitude of velocity, take the divide magnitude of momentum by the total mass of the players.
P = mv
P = (m₁ + m₂)v
1171.77 = (120 + 75)v <em>[solve for v]</em>
<em />v = 1171.77/195
v = 6.0091 ≈ 6.0 m/s
If asked to find direction, take inverse tan of x and y components.
tanθ = (y/x)
θ = tan⁻¹(1032/555)
[ θ = 61.73° north of east. ]
The magnitude of the velocity at which the two players move together immediately after the collision is approximately 6.0 m/s.
When electrons are lost a positive ion is formed. When electrons are gained, a negative ion is formed. I hope this helps
The answer to this statement is true!