8×1+5×(1/10)+9×(1/1000)
8+5×(.1)+9×(.001)
8+.5+.009
Answer is 8.509
Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
Answer:
2n
Step-by-step explanation:
Pythagoras 
2 squared plus 2 squared = 8 but you need to find out the root of 8,
square root of 8 is a surd, so answer in that
50 paquetes restamos 2500 - 3250 nos da 750, eso lo dividimos en 15 y da 50 1ue es el resultado
