Answer:
The hundredths place
Expanation
6 is in the one's place
2 is in the theth's place
1 is in the hundredth's place
3 is in the thousandth's place
Hey, i’d love to help you but there seems to be a typo in your equation because a minus sign (or negative sign) can’t be raised to the power of 3.
Answer:
Large boxes are 18.25 kg
Small boxes are 15.25 kg
Step-by-step explanation:
This is a system of equations. You need to set up each equation first.
I am assigning x to be big boxes and y to be small boxes.
5x + 3y = 137
2x + 6y = 128
To solve, you will need to eliminate a variable. That means you will have to multiply one of the equations by a number to make it so a variable will be eliminated. I will be multiplying the top equation by -2.
-2 ( 5x + 3y = 137)
2x + 6y = 128
Distribute the -2 to everything in the parentheses in the first equation.
-10x - 6y = -274
2x + 6y = 128
Notice the 6y will go away because -6y + 6y = 0. Now add the equations together. The remaining equation is:
-8x = -146
Solve for x by dividing by -8.
x = 18.25
Now plug that into one of the original equations.
2(18.25) + 6y = 128.
36.5 + 6y = 128 Subtract 36.5 from each side
-36.5 -36.5
6y = 91.5 Divide by 6 to solve
y = 15.25
