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Taya2010 [7]
3 years ago
12

Someone please help me out:(

Mathematics
1 answer:
gogolik [260]3 years ago
5 0
SAS mmmmmmmmmmmmmmmmmmm
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Rewrite y =<img src="https://tex.z-dn.net/?f=%5Csqrt9%7Bx%7D%20%2B45" id="TexFormula1" title="\sqrt9{x} +45" alt="\sqrt9{x} +45"
tigry1 [53]

Answer:

(1) We have been given a function: y=\sqrt{9x}+45-2

We can rewrite it using translation is:  

It is the graph of y=\sqrt{9x} translated 45 units left and 2 units down.

(2) Now, y=\sqrt{x}-5-2

So this is the graph of y=\sqrt{x} translated 5 units right and 2 units down.

(3) y=\sqrt{x}+5-2

So, this is the graph of y=\sqrt{x} translated 5 units left and 2 units down.

(4) y=\sqrt[3]{x}+5-2

It is the graph of y=\sqrt[3]{x}

translated 5 units left and 2 units down.

(5) y=\sqrt[3]{x}+5-2

It is the graph of y=\sqrt[3]{x}

translated 5 units left and 2 units down.

8 0
3 years ago
I dont understand the math answer can you explain better please.
Lunna [17]

Answer:

Can you elaborate, please?

Step-by-step explanation:

7 0
3 years ago
Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
timofeeve [1]

Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
Suppose a claim is that the average pulse rates of women is μ = 73 and we wish to test this against an alternative hypothesis th
Pachacha [2.7K]

Answer:

P = 0.018

Step-by-step explanation:

In this problem, the null and alterantive hypothesis are:

H_0: \mu=73\\H_1: \mu \ne 73

If the sample has a size of n = 40, the degrees of freedom are 40-1 = 39.

If the value of the test statistic is t = 2.463, we can look up in a t-table to find the p-value. In this test, because the mean can be bigger than 73 or smaller than 73, we have to do a two-tailed test.

For a two-tailed test for t = 2.463 and df = 39, the P-value is P = 0.018.

8 0
4 years ago
Joe rode his bike 750 meters in three minutes. What was Joe’s average speed?
sergij07 [2.7K]

Answer:

250 Meters per Minute

Step-by-step explanation:

Its simple, Divide 750 Meters by the 3 minutes he took

3 0
3 years ago
Read 2 more answers
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