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Semenov [28]
3 years ago
6

find the Edgemont of active with the given volume 216 cubic units ,512 cubic inches ,and 1000 cubic feet ​

Mathematics
1 answer:
Arisa [49]3 years ago
8 0

Answer:

6, 8 and 10

Step-by-step explanation:

you take the cube root of all of the numbers

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PLS ANSWER QUICK
Alex17521 [72]

Answer & Step-by-step explanation:

First, we will multiply 5 by 28 to find out the total number of ages in the room.

5 * 28 = 140

Now, we will multiply 6 by 29 to find out the total number of ages in the room after the new person comes in.

6 * 29 = 174

Now, in order for us to find the age of the new person, then we will subtract 140 from 174.

174 - 140 = 34

So, the person that entered the room is 34 years old.

6 0
2 years ago
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Can u help me please better picture
gladu [14]

Hi, there.

For this question, we can apply the Pythagorean theorem a^2 + b^2 = c^2.

I'm sure you've seen this equation before, and they kind of tried to trip you up with this problem. Trust me, it's easier than it looks. Let's break it down.

Lengths a and b both have the value of 48, which means that the value s in \sqrt{2s^2} is 48, because the length of the hypotenuse is the same as the length and height squared multiplied by 2.

Plug in the value for c: a^2 + b^2 = (\sqrt{2s^2})^2

Plug in the value for s:

(\sqrt{2(48^2)})^2

Do the innermost exponents first:

(\sqrt{2(2304)})^2

The square root symbol and the power of 2 cancel each other out, so we are left with:

s = 2(2304), so the hypotenuse is 4608 inches.

4 0
3 years ago
Factor the GCF: -6x^4y^5 - 15x^3y^2 + 9x^2y^3
natta225 [31]
<span>-6x^4y^5 - 15x^3y^2 + 9x^2y^3

</span>-6x^4y^5 =  -2, 3, x, x, x, x,  y, y, y, y, y
15x^3y^2 =  -5, 3 x, x, x, y, y
9x^2y^3 =    3, 3 x, x, y, y, y

Each group has a 3 in common and each group has 2 x in common and each group has 2 y in common so the GCF = -3x^2y^2

Divide that out and we get 
\frac{-6x^4y^5 - 15x^3y^2 + 9x^2y^3}{-3x^2y^2} =
2x^2y^3 + 5x - 3y
-3x^2y^2(2x^2y^3 + 5x - 3y)

5 0
3 years ago
Which expression is equivalent to 300f2−90f?
jenyasd209 [6]
30f(10f-3) just trust me
4 0
3 years ago
I NEED HELP PLEASE! THANKS :)
Marianna [84]

Answer:

<em>y = 2 \: cos \:  (\frac{1}{3} x)</em>

<em>option</em><em> </em><em>C</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>option</em><em>.</em>

<em>Expla</em><em>nation</em><em>:</em>

<em>General</em><em> </em><em>expression</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>cosine</em><em> </em><em>function</em><em> </em><em>is</em><em>:</em>

<em>y</em><em>=</em><em>A</em><em> </em><em>cos</em><em> </em><em>k</em><em> </em><em>X</em>

<em>where</em><em> </em><em>A</em><em> </em><em>is</em><em> </em><em>amplitude </em><em>and</em><em> </em><em>2</em><em> </em><em>pi</em><em>/</em><em>k</em><em> </em><em>is</em><em> </em><em>its </em><em>period.</em>

<em>In</em><em> </em><em>our</em><em> </em><em>case</em><em>,</em>

<em>- y = 2 \: cos \:  (\frac{1}{3} x) \:</em>

<em>has</em><em> </em><em>:</em>

<em>amplitude = 2 \\ period = 2\pi \times 3 = 6\pi</em>

<em>hence,</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>C</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

7 0
3 years ago
Read 2 more answers
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