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GREYUIT [131]
3 years ago
5

D) Round 0.00208815 to 3 significant figures.

Mathematics
2 answers:
Lostsunrise [7]3 years ago
8 0

Answer:

= 0.00209

Step-by-step explanation:

JulijaS [17]3 years ago
8 0
With my calculation the answer would be 0.00209
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Express 0.00386×10-4 in standard form?(Urgent....Answer if sure)
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0.000000386

Step-by-step explanation:

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3 years ago
How to simplify the square root of 3 over the square root of 21
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3 * 7 = 21, so

\sqrt{21}=\sqrt{3\cdot7}=\sqrt3\sqrt7

Then

\dfrac{\sqrt3}{\sqrt{21}}=\dfrac1{\sqrt7}

and you can rationalize the denominator to write this as

\dfrac1{\sqrt7}\cdot\dfrac{\sqrt7}{\sqrt7}=\dfrac{\sqrt7}7

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4 years ago
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A farm lets you pick 3 pints of raspberries for $12.00.
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Use the "rule of 72" to estimate the doubling time (in years) for the interest rate, and then calculate it exactly. (Round your
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Answer:

According to the rule of 72, the doubling time for this interest rate is 8 years.

The exact doubling time of this amount is 8.04 years.

Step-by-step explanation:

Sometimes, the compound interest formula is quite complex to be solved, so the result can be estimated by the rule of 72.

By the rule of 72, we have that the doubling time D is given by:

D = \frac{72}{Interest Rate}

The interest rate is in %.

In our exercise, the interest rate is 9%. So, by the rule of 72:

D = \frac{72}{9} = 8.

According to the rule of 72, the doubling time for this interest rate is 8 years.

Exact answer:

The exact answer is going to be found using the compound interest formula.

A = P(1 + \frac{r}{n})^{nt}

In which A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

So, for this exercise, we have:

We want to find the doubling time, that is, the time in which the amount is double the initial amount, double the principal.

is double the initial amount, double the principal.

A = 2P

r = 0.09

The interest is compounded anually, so n = 1

A = P(1 + \frac{r}{n})^{nt}

2P = P(1 + \frac{0.09}{1})^{t}

2 = (1.09)^{t}

Now, we apply the following log propriety:

\log_{a} a^{n} = n

So:

\log_{1.09}(1.09)^{t} = \log_{1.09} 2

t = 8.04

The exact doubling time of this amount is 8.04 years.

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