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sveta [45]
2 years ago
8

A 15. 0 cm object is 12. 0 cm from a concave mirror that has a focal length of 4. 8 cm. Its image is 8. 0 cm in front of the mir

ror. What is the approximate height of the image produced by the mirror? –4 cm –10 cm 10 cm 4 cm.
Mathematics
1 answer:
Pachacha [2.7K]2 years ago
6 0

Answer:

-10

Step-by-step explanation:

right on edge 2022

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6c+14=−5c+4+9c<br><br> What does C equal?
maria [59]

Answer: c = -5

Step-by-step explanation:

6c+14=-5c+4+9c

Combine like terms

6c+14=4c+4

Subtract 4c from both sides.

-4c+6c+14=4c+4-4c\\2c+14=4

Subtract 14 from both sides.

2c+14-14=4-14\\2c=-10\\

Divide by 2 to isolate c

\frac{2c}{2}=\frac{-10}{2}\\  c=-5

Check:

6c+14=-5c+4+9c\\6(-5)+14=-5(-5)+4+9(-5)\\-30+14=25+4-45\\-16=29-45\\-16=-16

6 0
4 years ago
Read 2 more answers
Help with all please!
Elena L [17]
For 14, 15, and 16 you would move the decimal the number in the exponent to the left because the exponent is negative. For example 14 would be .00000030
3 0
4 years ago
What is the day 1,000,000 days from now?
Deffense [45]
<span>From Today (Monday 21 November 2016) it will be Tuesday 19th October 4754</span>
6 0
3 years ago
Evaluate C7, 5).<br><br> A. 21<br><br> B. 42<br><br> C. 1,008
faltersainse [42]
<h3>Answer: A.  21</h3>

=======================================

C(n, r) = (n!)/(r!*(n-r)!) is the combination formula

C(7, 5) = (7!)/(5!*(7-5)!)

C(7, 5) = (7!)/(5!*2!)

C(7, 5) = (7*6*5!)/(5!*2!)

C(7, 5) = (7*6)/(2!) ..... note the "5!" terms divided and canceled

C(7, 5) = (7*6)/(2*1)

C(7, 5) = 42/2

C(7, 5) = 21

4 0
3 years ago
Sin 1 + sin 2 + sin3 .................+ sin 360 = ?
lesya [120]

Assuming that arcs are given in degrees, call S the following sum:

S = sin 1° + sin 2° + sin 3° + ... + sin 359° + sin 360°


Rearranging the terms, you can rewrite S as

S = [sin 1° + sin 359°] + [sin 2° + sin 358°] + ... + [sin 179° + sin 181°] + sin 180° +
   + sin 360°

S = [sin 1° + sin(360° – 1°)] + [sin 2° + sin(360° – 2°)] + ...+ [sin 179° + sin(360° – 179)°]
   + sin 180° + sin 360°          (i)


But for any real k,

sin(360° – k) = – sin k


then,

S = [sin 1° – sin 1°] + [sin 2° – sin 2°] + ... + [sin 179° – sin 179°] + sin 180° + sin 360°

S = 0 + 0 + ... + 0 + 0 + 0        (... as sin 180° = sin 360° = 0)

S = 0


Each pair of terms in brackets cancel out themselves, so the sum equals zero.

∴   sin 1° + sin 2° + sin 3° + ... + sin 359° + sin 360° = 0          ✔


I hope this helps. =)


Tags:  <em>sum summatory trigonometric trig function sine sin trigonometry</em>

4 0
3 years ago
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