Answer:

And we can use the following formula:

And replacing the info we got:

Step-by-step explanation:
We define two events for this case A and B. And we know the probability for each individual event given by the problem:


And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:


And for this special case we want to find this probability:

And we can use the following formula:

And replacing the info we got:

See the attached picture:
Answer:
y = - 3x + 4
Step-by-step explanation:
Line is passing through the points (1, 1) & (0, 4)
Slope of line = (4-1)/(0-1) = 3/(-1) = - 3
Equation of line
y = mx + b
Here m = - 3, b = 4
y = - 3x + 4
Using point (1, 1)
y - 1= - 3(x - 1)
y = - 3x +3 +1
y = - 3x + 4
Answer: last option.
Step-by-step explanation:
- Subtract the fractions that are in the numerator.
- Add the fractions that are in the denominator.
Then:

- Multiply the numerator of the fraction on the top by the denomianator of the fraction on the bottom.
- Simplify.
Then:
