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adelina 88 [10]
3 years ago
14

George arranges the icons on his computer desktop into 4 rows of 2 icons. How many icons are on George’s desktop? Make an array

to answer the question.
NEED ANSWER ASAP THIS QUESTION MAKES NO SENSE
I added the graph to help you get your bearings
Answers:
A:2
B:4
C:6
D:8
im giving 45 points to whoever answers

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer:

4

Step-by-step explanation:

Every four rows there are two icons.

I hope this helped

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Kevin bought 3 dvds for 45.99 how much would 7 dvds cost?
Alecsey [184]

Answer:

I am pretty sure the answer would be $107.31. Sorry if I'm wrong.

Step-by-step explanation:

First you take the total of the 3 DVD's (45.99) and you divide that by 3 (number of DVD's) to get 15.33 which is called the unit price. Then, you take your unit price and multiply that by how many items you are going to buy.

45.99 / 3 = 15.33

15.33 x 7 = 107.31

6 0
3 years ago
Please help me!
Sindrei [870]
Well, let's check if your inequality is true. We have to add the 3 scores up and divide them by 3 to know the average.

73 + 81 + 86 = 240
240 / 3 = 80

80%

That's true, now let's check 101.

73 + 81 + 101 = 255
255 / 3 = 85

85%

That's true.

Your inequality is correct.
5 0
3 years ago
Juan read 300 pages in 5 days. Which reading rate is equivalent
Marta_Voda [28]
60 pages in one day 1/60
6 0
3 years ago
(30 POINTS AND BRAINLIEST FOR BEST)
Romashka-Z-Leto [24]

Part A)

Multiply the amount he earned by 8.5%

8.5% written as a decimal is 0.085.

75,000 x 0.085 = $6,375

Part B)

Subtract the amount of tax from his earnings:

75,000 - 6,375 = $68,625

8 0
3 years ago
A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and
mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

\mu = \frac{3X_{1} + 4X_{2}  }{8}

Now

Bias for the estimator = E(μ bar) - μ

                                    = E( \frac{3X_{1} + 4X_{2}  }{8}) - 4.5

                                    = \frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5

                                    = \frac{3(4.5) + 4(4.5)}{8} - 4.5

                                    = \frac{13.5 + 18}{8} - 4.5

                                    = \frac{31.5}{8} - 4.5

                                    = 3.9375 - 4.5

                                    = - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

                                                             = Var(μ bar) + [Bias(μ bar, μ)]²

                                                             = Var( \frac{3X_{1} + 4X_{2}  }{8}) + 0.3136

                                                             = \frac{1}{64} Var( {3X_{1} + 4X_{2}  }) + 0.3136

                                                             = \frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})]  }) + 0.3136

                                                             = \frac{1}{64} [{3(57.76) + 4(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [7(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [404.32]  } + 0.3136

                                                             = 6.3175 + 0.3136

                                                              = 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0
3 years ago
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