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2 years ago

Try to create a triangle with angle measures 20°, 50°, and 80°. Which of the following describes the figure?

Mathematics

1 answer:

antiseptic1488 [7]2 years ago

8 0

Answer:

it is a triangle whose sides appear to be all different lengths

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Suppose you add two linear equations that form a system, and you get the result −5 = −5. How many solutions does the system have

exis [7]

Infinite amount of solutions

6 0

3 years ago

A local salesman receives a base salary of $975 monthly. He also receives a commission of 7% on all sales over $1250. How much w

slava [35]

Answer:

$17,321.43

Step-by-step explanation:

The amount of monthly income from commissions would have to be ...

$2100 -975 = $1125

This is 7% of sales over $1250, so the sales (s) would need to be ...

1125 = 0.07(s -1250)

1125 = .07s -87.50 . . eliminate parentheses

1212.50 = 0.07s . . . . add 87.50

17,321.43 = s . . . . . . . divide by 0.07

He would have to sell $17,321.43 in a month if he needed an income of $2100.

8 0

2 years ago

Write the equation of each line using the given information.

MrRissso [65]

Answer:

See explanation.

Step-by-step explanation:

We need a point and a slope to have a point slope equation.

$y-y_{1}=m(x-x_{1})$

We need a slope and y-intercept to write in slope intercept form.

$y=mx+b$

A) $y-1=\frac{1}{2}(x+4)$ or $y=\frac{1}{2}x+3$

B) $y+1=-1(x-2)$

C) $y-1=0(x-1)$

D) $y=-3x+8$

4 0

3 years ago

100xyz-75xy factor completely

yarga [219]

the factored form is

-25xy(-4z+3)

6 0

3 years ago

Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x>1

Lera25 [3.4K]

Assuming the function is

$f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}$

For $f(x)$ to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)$
$\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)$
$\iff2=b+c$

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

$f'(x)=\begin{cases}2&\text{for }x1\end{cases}$

$\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)$
$\iff2=2b+c$

Now we solve for $b$ and $c$ :

$\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2$

5 0

3 years ago