The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)
<h3>What is the area of the quadrilateral?</h3>
Herein we have a description of an <em>irregular</em> quadrilateral, whose area must be determined by adding the areas of minor quadrilaterals and triangles that are part of it. The area is now determined:
A = 0.5 · (24 cm) · (7 cm) + 0.5 · (15 cm) · (20 cm)
A = 234 cm²
The area of the <em>irregular</em> quadrilateral ABCD is equal to 234 square centimeters. (Correct choice: C)
<h3>Remark</h3>
The picture with the quadrilateral is missing and is included as attachment.
To learn more on quadrilaterals: brainly.com/question/13805601
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Plug in x values to solve for y values and then plot them in a graph. connect the dots with a line
Answer is C x=1 because that’s the middle of it.
Mary needs to mow 2/5 of the lawn to finish the remaining section. Mary needs to mow 2,000 square feet. You find your answer by first diving 5000/5=1000 to see how big the sections are. You do 1000x2=2,000 to find how much Mary has to mow
Answer:
The answer is
One: 28, 29, 30
Two: 75,77
Step-by-step explanation:
One
Let the three numbers be (x - 1) , x , and x + 1
(x - 1) + x + (x +1 ) - 12 = 75 Remove the brackets
x - 1 + x + x + 1 - 12 = 75 Combine the like terms on the left
3x - 12 = 75 Add 12 to both sides
3x = 75 + 12
3x = 87 Divide by 3
x = 87/3
x = 29
Two
Let the first odd number = 2x -1
Let the second odd number = 2x + 1
2x - 1 + 2x + 1 + 18 = 170 Combine like terms on the left.
4x + 18 = 170 Subtract 18 from both sides.
4x = 170 - 18 Combine like terms on the right
4x = 152 Divide by 4
4x/4 = 152/4
x = 38
2 * 38 - 1 = 75
2 * 38 + 1 = 77
