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natulia [17]
3 years ago
8

The angle looking up at the sun is 70°. A flagpole casts a shadow of 15 ft. Draw a diagram and find the height of the flagpole

Mathematics
2 answers:
pav-90 [236]3 years ago
7 0

Answer:

Option A is correct

the height of the flagpole is, 41.2 ft

Step-by-step explanation:

As per the statement:

The angle looking up at the sun is 70°

⇒\theta= 70^{\circ}

It is also given that:

A flagpole casts a shadow of 15 ft.

For this you can see the diagram as shown below in the attachment.

Now, find the height of the flagpole.

Let h be the height of flagpole.

using tangent ratio:

\tan \theta = \frac{\text{Opposite side}}{\text{Adjacent side}}

From the given diagram;

\theta = 70^{\circ}

Opposite side = Height of the Flag pole = h

Adjacent  side = Shadow of the flagpole = 15 ft

Substitute these we get;

\tan 70^{\circ} = \frac{h}{15}

Multiply both sides by 15 we get;

15 \cdot \tan 70^{\circ} = h

15 \cdot 2.75 = h

Simplify:

41.2 ft = h

or

h = 41.2 ft

Therefore, the height of the flagpole is, 41.2 ft

dangina [55]3 years ago
5 0

Answer:

The length of the flagpole be 41.2 ft .

Option (A) is correct .

Step-by-step explanation:

As given

The angle looking up at the sun is 70°.

A flagpole casts a shadow of 15 ft .

Now by using the trignometric identity .

tan \theta = \frac{Perpendicular}{Base}

\ theta = 70^{\circ}

tan\ 70^{\circ} = \frac{AB}{BC}

BC = 15 ft

tan 70° = 2.75 (Approx)

2.75 = \frac{AB}{15}

AB = 2.75 × 15

     = 41.2 ft

Therefore the length of the flagpole be 41.2 ft .

Option (A) is correct .

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stira [4]

Answer:

The equation of the perpendicular line 't' is  3x+y =0

Point slope form y = mx +C

                            y = - 3x

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation  s = \frac{1}{3}x +10    and given point (1,-3)

The equation of the perpendicular line

                        y =\frac{x+30}{3}

                 ⇒  3 y = x+30

               ⇒ x - 3y +30 =0

<u><em>Step(ii):-</em></u>

<em>The perpendicular line of the given straight line 's'</em>

<em>        b x -ay +k=0</em>

⇒  -3x -y +k=0

This line is passing through the point (1,-3)

     -3(1)-(-3)+k=0

            k =0

The equation of the perpendicular line   -3x-y =0

<u><em>Final answer:-</em></u>

The equation of the perpendicular line   3x+y =0

Point slope form y = mx +C

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