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natulia [17]
3 years ago
8

The angle looking up at the sun is 70°. A flagpole casts a shadow of 15 ft. Draw a diagram and find the height of the flagpole

Mathematics
2 answers:
pav-90 [236]3 years ago
7 0

Answer:

Option A is correct

the height of the flagpole is, 41.2 ft

Step-by-step explanation:

As per the statement:

The angle looking up at the sun is 70°

⇒\theta= 70^{\circ}

It is also given that:

A flagpole casts a shadow of 15 ft.

For this you can see the diagram as shown below in the attachment.

Now, find the height of the flagpole.

Let h be the height of flagpole.

using tangent ratio:

\tan \theta = \frac{\text{Opposite side}}{\text{Adjacent side}}

From the given diagram;

\theta = 70^{\circ}

Opposite side = Height of the Flag pole = h

Adjacent  side = Shadow of the flagpole = 15 ft

Substitute these we get;

\tan 70^{\circ} = \frac{h}{15}

Multiply both sides by 15 we get;

15 \cdot \tan 70^{\circ} = h

15 \cdot 2.75 = h

Simplify:

41.2 ft = h

or

h = 41.2 ft

Therefore, the height of the flagpole is, 41.2 ft

dangina [55]3 years ago
5 0

Answer:

The length of the flagpole be 41.2 ft .

Option (A) is correct .

Step-by-step explanation:

As given

The angle looking up at the sun is 70°.

A flagpole casts a shadow of 15 ft .

Now by using the trignometric identity .

tan \theta = \frac{Perpendicular}{Base}

\ theta = 70^{\circ}

tan\ 70^{\circ} = \frac{AB}{BC}

BC = 15 ft

tan 70° = 2.75 (Approx)

2.75 = \frac{AB}{15}

AB = 2.75 × 15

     = 41.2 ft

Therefore the length of the flagpole be 41.2 ft .

Option (A) is correct .

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nadezda [96]

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8 1/3 x 12 = 100

100 is the answer

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3 years ago
find the parametric equations for the line of intersection of the two planes z = x + y and 5x - y + 2z = 2. Use your equations t
Kaylis [27]

Answer:

You didn't give the points in which you want the parametric equations be filled, but I have obtained the parametric equations, and they are:

x = (1/3 + t)

y = (-1/3 - 7t)

z = -6t

Step-by-step explanation:

If two planes intersect each other, the intersection will always be a line.

The vector equation for the line of intersection is given by

r = r_0 + tv

where r_0 is a point on the line and v is the vector result of the cross product of the normal vectors of the two planes.

The parametric equations for the line of intersection are given by

x = ax, y = by, and z = cz

where a, b and c are the coefficients from the vector equation

r = ai + bj + ck

To find the parametric equations for the line of intersection of the planes.

x + y - z = 0

5x - y + 2z = 2

We need to find the vector equation of the line of intersection. In order to get it, we’ll need to first find v, the cross product of the normal vectors of the given planes.

The normal vectors for the planes are:

For the plane x + y - z = 0, the normal vector is a⟨1, 1, -1⟩

For the plane 5x - y + 2z = 2, the normal vector is b⟨5, -1, 2⟩

The cross product of the normal vectors is

v = a × b =

|i j k|

|1 1 -1|

|5 -1 2|

= i(2 - 1) - j(2 + 5) + k(-1 - 5)

= i - 7j - 6k

v = ⟨1, -7, -6⟩

We also need a point on the line of intersection. To get it, we’ll use the equations of the given planes as a system of linear equations. If we set z = 0 in both equations, we get

x + y = 0

5x - y = 2

Adding these equations

5x + x + y - y = 2 + 0

6x = 2

x = 1/3

Substituting x = 1/3 back into

x + y = 0

y = -1/3

Putting these values together, the point on the line of intersection is

(1/3, -1/3, 0)

r_0= (1/3) i - (1/3) j + 0 k

r_0​​ = ⟨1/3, -1/3, 0⟩

Now we’ll plug v and r_0​​ into the vector equation.

r = r_0​​ + tv

r = (1/3)i - (1/3)j + 0k + t(i - 7j - 6k)

= (1/3 + t) i - (1/3 + 7t) j - 6t k

With the vector equation for the line of intersection in hand, we can find the parametric equations for the same line. Matching up r = ai + bj + ck with our vector equation,

r = (1/3 + t) i + (-1/3 - 7t) j + (-6t) k

a = (1/3 + t)

b = (-1/3 - 7t)

c = -6t

Therefore, the parametric equations for the line of intersection are

x = (1/3 + t)

y = (-1/3 - 7t)

z = -6t

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son4ous [18]

Answer:

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Triangular prism = 1/2(9)(6)(12)=324

540+324=864 cubic meters

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Sliva [168]
Hi there!

To find this you can simply use a calculator. All you have to do is divide the numerator by the denominator to see what you get.

7/200 in decimal form is 0.035. Pretty simple.
This fraction cannot be simplified.

Hope this helps!
8 0
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