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4 years ago

75 liters is equivalent to how many quarts?

Mathematics

1 answer:

lutik1710 [3]4 years ago

4 0

Answer:

79.2516 quarts

Step-by-step explanation:

Since there is 1.05669 quart(s) in one liter, you would have to multiply this number by 75. Hope this helped!

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There are 24 carnations in each bunch and 12 roses in each bunch. Use your expression from question 1 or question 2 to determine

Pie

Answer: r/c

Step-by-step explanation:

96/48

24/12

8 0

3 years ago

PLEASE HELP!!!!!!<br><br> I really need help on this! It's due today and I'm kinda late on it!!

Margaret [11]

Answer:

1.not 2×4 is 2+4 answer should be 6x⁶

2.not 3+4 is 3×4 answer should be 12a⁷

3.miss 1 should x^(6+1+3) should be x¹⁰

4.base different, and just become 81×8=648

3 0

3 years ago

Two-thirds of a number decreased by three is five equation form

enot [183]

Answer:

2/3x - 3 = 5

Step-by-step explanation:

Let x be the number

2/3x - 3 = 5

Add 3 to each side

2/3x-3+3 = 5+3

2/3x = 8

Multiply each side by 3/2

3/2*2/3x = 8*3/2

x = 12

5 0

3 years ago

Guest ages at a ski mountain resort typically have a right-skewed distribution. Assume the standard deviation (σ) of age is 14.5

ValentinkaMS [17]

Answer: (30.49 years, 42.31 years)

Step-by-step explanation:

The formula to find the confidence interval is given by :-

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}.$

, where $\overline{x}$ = Sample mean

z* = Critical value.

$\sigma$ = Population standard deviation.

n= Sample size.

As per given , we have

$\overline{x}=36.4$

$\sigma=14.5$

n= 40

We know that the critical value for 99% confidence interval : z* = 2.576 (By z-table)

A 99 percent confidence interval for µ, the true mean age of guests will be :

$36.4\pm (2.576)\dfrac{14.5}{\sqrt{40}}\\\\ 36.4\pm (2.576)2.29265130362\\\\=36.4\pm5.90586975813\\\\\approx36.4\pm5.91\\\\=(36.4-5.91,\ 36.4+5.91)\\\\=(30.49,\ 42.31)$

∴ a 99 percent confidence interval for µ, the true mean age of guests = (30.49 years, 42.31 years)

7 0

3 years ago

Write the first five terms of the the sequence defined by the explicit formula an=72(1/3)^n-1

lisabon 2012 [21]

$a_n=72\left(\dfrac{1}{3}\right)^{n-1}\\\\\text{Put}\ n=1,\ n=2,\ n=3,\ n=4,\ n=5\ \text{to the equation}:\\\\n=1\to a_1=72\left(\dfrac{1}{3}\right)^{1-1}=72\left(\dfrac{1}{3}\right)^0=72(1)=72\\\\n=2\to a_2=72\left(\dfrac{1}{3}\right)^{2-1}=72\left(\dfrac{1}{3}\right)^1=72\left(\dfrac{1}{3}\right)=\dfrac{72}{3}=24\\\\n=3\to a_3=72\left(\dfrac{1}{3}\right)^{3-1}=72\left(\dfrac{1}{3}\right)^2=72\left(\dfrac{1}{9}\right)=\dfrac{72}{9}=8\\\\n=4\to a_4=72\left(\dfrac{1}{3}\right)^{4-1}=72\left(\dfrac{1}{3}\right)^3=72\left(\dfrac{1}{27}\right)=\dfrac{72}{27}=\dfrac{8}{3}\\\\n=5\to a_5=72\left(\dfrac{1}{3}\right)^{5-1}=72\left(\dfrac{1}{3}\right)^4=72\left(\dfrac{1}{81}\right)=\dfrac{72}{81}=\dfrac{8}{9}\\\\Answer:\ \boxed{72,\ 24,\ 8,\ \dfrac{8}{3},\ \dfrac{8}{9}}$

8 0

3 years ago

Read 2 more answers