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Darya [45]
3 years ago
15

If math students typically earn 24 points out of 35 possible on a test, how many points would be typical if there were 100 possi

ble points? Round to the nearest tenth
Mathematics
1 answer:
Lilit [14]3 years ago
5 0

Answer:

68.6

Step-by-step explanation:

Given the initial ratio of 24 points out of 35 possible points, you can set up a proportion (equivalent ratios) to find the expected number of points math students would ear on a test of 100 possible points:

\frac{earned}{possible}=\frac{24}{35}=\frac{x}{100}

Where 'x' is the number of points earned on the 100 point test.

Cross-multiply: 35x = 24(100) or 35x = 2400

Divide both sides by 35: 35x/35 = 2400/35

Solve for x:  x = 68.6

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By applying the equation of dilation, the coordinates of the vertices of the triangle ABC are A'(x, y) = (-12, 0), B'(x, y) = (0, -9) and C'(x, y) = (-12, -9).

<h3>How to find the image of a triangle</h3>

A dilation is a type of <em>rigid</em> transformation. <em>Rigid</em> transformations are transformations applied to <em>geometric</em> loci such that <em>Euclidean</em> distances are conserved.

There is a triangle and its image must be a triangle, the <em>new</em> triangle is found by transforming the three vertices of the prior one following this formula:

A'(x, y) = P(x, y) + k · [A(x, y) - P(x, y)]     (1)

Where:

  • P(x, y) - Center of reflection.
  • A(x, y) - Original vertex
  • A'(x, y) - New vertex
  • k - Dilation factor

If we know that P(x, y) = (0, 0), A(x, y) = (-4, 0), B(x, y) = (0, -3) and C(x, y) = (-4, -3), then the new vertices of the triangle are, respectively:

Point A

A'(x, y) = (0, 0) + 3 · [(-4, 0) - (0, 0)]

A'(x, y) = (-12, 0)

Point B

B'(x, y) = (0, 0) + 3 · [(0, -3) - (0, 0)]

B'(x, y) = (0, -9)

Point C

C'(x, y) = (0, 0) + 3 · [(-4, -3) - (0, 0)]

C'(x, y) = (-12, -9)

Lastly, we draw the two triangles, which are presented in the image attached below.

To learn more on dilations: brainly.com/question/13176891

#SPJ1

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