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IgorLugansk [536]
3 years ago
11

Least common multiple of 3,18,and 9

Mathematics
1 answer:
wariber [46]3 years ago
8 0

Answer:

18

Step-by-step explanation:

Lets factor each of them:

3:1,3

18:2*3^2

9:3^2

every factor is in 18:2,3,3...

Therefore the answer is 18.

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Solve by elimination: x-2y= -7 ; 4x+2y= 22
svp [43]
Apply the elimination method to the 2y terms since they are opposites & therefore can eliminate. Combine the rest of the terms, vertically.

x-2y= -7
4x+2y= 22
5x = 15
Divide both sides by 5.
x=3

Plug the x value to one of the original equations and solve for y.

4x + 2y = 22
4(3) + 2y = 22
12 + 2y = 22
Subtract by 12 on both sides.
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Answer : The specific heat of the metal is, 2178.67J/kg^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of metal = ?

c_2 = specific heat of ice = 2000J/kg^oC

m_1 = mass of metal = 1.00 kg

m_2 = mass of ice = 1.00 kg

T_f = final temperature of mixture = -8.88^oC

T_1 = initial temperature of metal = 5.00^oC

T_2 = initial temperature of ice = -24.0^oC

Now put all the given values in the above formula, we get:

(1.00kg)\times c_1\times (-8.88-5.00)^oC=-[(1.00kg)\times 2000J/kg^oC\times (-8.88-(-24.0))^oC]

c_1=2178.67J/kg^oC

Therefore, the specific heat of the metal is, 2178.67J/kg^oC

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