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Kryger [21]
3 years ago
5

a convention manager finds that she has $1,290 made up of 20 and 50s she has a total of 42 bills how many of each kind does she

have​
Mathematics
1 answer:
love history [14]3 years ago
4 0

15 $50 dollar bills and 27 $20 dollar bills, a total of 42 bills

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The items Matt ate at dinner cost m dollars. He added 6.5% to the cost of dinner for sales tax. Matt paid $25 using a gift card
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Answer:

there isn;t anything posted underneath

Step-by-step explanation:

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3 years ago
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jack has 6 pounds of candy, he plans on splitting it up equally with his 5 students how many pounds will each student get?
uysha [10]
The answer will be 1.2
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One hiking club charges $16 to become a member and $3 to participate on each hike. Another club charges no membership fee, but c
yawa3891 [41]

Answer:

x < 8

Step-by-step explanation:

x= # of hikes

3x +16 =5x

-3x. -3x

16=2x

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8=x

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check:

3(8) +16 =5(8)

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40=40 ✓

there for at 8 hikes with either deal it would be the same but if you went up a number of hikes for the first option it would only be $43.00 spent in total. but with the second option it would be $45.00.

7 0
3 years ago
Original price of a pen: $49.95; Tax: 3% <br> The cost would be?
elixir [45]

Answer:

49.98

Step-by-step explanation:

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A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent
kotykmax [81]

Answer:

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

Step-by-step explanation:

\bar X_{1}=15 represent the mean for sample 1

\bar X_{2}=18 represent the mean for sample 2

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=49 sample size for the group 2  

n_{2}=64 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

And the degrees of freedom are given by df=n_1 +n_2 -2=49+64-2=111  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897

P value

Since is a bilateral test the p value would be:  

p_v =2*P(t_{111}  

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

7 0
3 years ago
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