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3 years ago

A rectangle measures 1200 cm by 2 m. Find the perimeter of the rectangle.

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

4 0

Answer:

Perimeter = 28 mt or 2800 cms

Step-by-step explanation:

Formula for Perimeter is

P = 2(l+b)

Here P = we have to find

Length = l = 1200 cm Given

Width = b = 2 m = 200 cm (Given and converted into cm as the units must be same)

Putting those values in the formula

P=2(1200+200)

P=2(1400)

P=2800 cm

P=28 mt

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Bingel [31]

Pretty sure x is 4 in #9

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3 years ago

33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

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g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

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4 years ago

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sergiy2304 [10]

(10 elements..........) 2^(10)=1024
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3 years ago

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Sophie [7]

Answer:

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tia_tia [17]

Answer:

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