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4 years ago

What is the value of g

Mathematics

1 answer:

kompoz [17]4 years ago

5 0

Answer:

27 degrees

Step-by-step explanation:

So basically 52.1 and g is the same as 79.1 so your equation is 52.1+g=79.1

So first you would subtract 52.1 from both sides g=27

Then basically you have the answer

So therefore g=27

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Erin feeds her dog 7/10 cup of food a day . With 3/10 cup canned and the rest dry . She also gives her dog 1 treat a day . How m

gavmur [86]

Answer:

$2\frac{4}{5}\ \ or \ 2.8 \ \ cups$

Step-by-step explanation:

-The total portion fed to the dog is 7/10 cup

Canned-3/10
Dry=7/10-3/10=4/10

-One week has 7 days. we multiply the dry portion per day by the number of days in a week.

$Dry= Total -Canned\\\\=\frac{7}{10}-\frac{3}{10}\\\\=0.40 \ cup\\\\Dry \ per \ Week= Dry/ day\times days\\\\=0.40\times 7\\\\=2\frac{4}{5}\ or\ 2.8 \ cups$

Hence, Erin feed her dog 2 4/5 0r 2.8 cups of dry food

5 0

3 years ago

The personnel department of a large corporation wants to estimate the family dental expenses of its employees to determine the f

Verizon [17]

Answer:

CI(95%): [205,5;400.8]dolars

Step-by-step explanation:

Hello!

So you need to construct a confidence interval for the average family dental expenses (μ) using the sample given in the problem. To estimate it you need to first choose a statistic. For this small sample, considering that the variable has a normal distribution (I made a quick Shapiro Wilks test, with p-value 0.3234, you can assume normality) the best statistic to use is the Student's t-test.

t= [x(bar)-μ]/S/√n ≈ t₍ₙ₋₁₎

The formula for the confidence interval to estimate the mean is

x(bar)± $t_{n-1; 1-\alpha/2}$ * (S/√n)

The critical value is from a t-distribution with 11 degrees of freedom

± $t_{n-1; 1-\alpha/2} = t_{11; 0.975} = 2.201$

>remember since it's two-tailed, to get the right critical value you have to divide α by 2. So in the text, you received a confidence level of 1-α=0.95 so α=0.05 then α/2=0.025 and 1-α/2=0.975

To construct the interval, you need to first calculate the sample mean and the standard derivation.

Sample

115; 370; 250; 593; 540; 225; 117; 425; 318; 182; 275; 228

n= 12

∑xi = 3638 ∑xi² = 1362670

Sample mean

x(bar): (∑xi)/n = 3638/12 = 303.17 dolars

Standard derivation

S²= 1/n-1*[∑xi²- (∑xi)²/n] = 1/11 * [1362670-((3638)²/12)] = 23614.47 dolars²

S= 153.67 dolars

Confidence interval (95%)

303.17± 2.201* (153.67/√12)