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maw [93]
3 years ago
11

Next four multiples of the unit fraction:1/2

Mathematics
1 answer:
Alexxandr [17]3 years ago
8 0
4 multiples of the fraction 1/2 are 2/4,4/8,6/12,8/16, and so on.There are a lot of multiples for 1/2. Hope those 4 multiples help you out.  :)
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Find the student's error in solving the following
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x>7

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when dividing by a (-)

the inequality sign changes

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This month, Chun’s office produced 690 pounds of garbage. Chun wants to reduce the weight of garbage produced to 85% of the weig
Effectus [21]
Chun wants to <span>reduce the weight of garbage produced to 85% of the weight produced this month. 
This means that, Chun's garbage weight next month should be equal to 85% of his garbage weight this month.

Translating this into an equation, we will find that:
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8 0
3 years ago
Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
Can someone help me with this problem?
Lena [83]
The only answer that makes sense to me is B.
3 0
3 years ago
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