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Ratling [72]
3 years ago
15

What is the sum of 2/2 plus 3/3 represent your answer with multiple ways

Mathematics
1 answer:
devlian [24]3 years ago
8 0

Answer:

2

Step-by-step explanation:

1. 2/2=1, 3/3=1, 1+1=2


2.Find common denominator: 6/6+6/6=12/6=2

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(Find the length of the missing side in each triangle)​
just olya [345]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The relevant trig relations are summarized by the mnemonic SOH CAH TOA. This means ...

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

  Tan = Opposite/Adjacent

So, for each triangle, determine the relationships of the given sides to the given angle: adjacent, opposite, or hypotenuse. Then write and solve the equation using one of the above templates.

4 0
3 years ago
1 x (3 + 7) = (1 x 3) + (1 x 7) is an example of which property?
Crazy boy [7]

Answer:

distributive property

Step-by-step explanation:

they distribute the 1 to the 3 and 7 to make it easier

hope this helps

6 0
3 years ago
Given f (x) = 1/3 (x +6) what is f (-6)?<br><br>help me pretty please!!​
Blizzard [7]

Answer:

  0

Step-by-step explanation:

Put -6 where x is and do the arithmetic.

  f(-6) = 1/3 (-6 +6) = 1/3 (0)

  f(-6) = 0

3 0
3 years ago
Read 2 more answers
5.1(3 + 2.2x) &gt; –14.25 – 6(1.7x + 4)?
MaRussiya [10]

Answer:

x > -2.5

Step-by-step explanation:

1) 5.1 (3 + 2.2x) > -14.25 - 6 (1.7x + 4)

2) 15.3 + 11.22x > -14.25 - 10.2x - 24

3) 15.3 + 11.22x > -38.25 - 10.2x

4) 11.22x + 10.2x > -38.25 - 15.3

5) 21.42x > -53.55

6) x > -2.5

Alternate forms

x > -5/2x or x > -2 1/2

5 0
3 years ago
Please help me! I don't understand this! DUE TODAY
pishuonlain [190]
Answer: See the answers below.

The first equation that needs to be solve is: 10 = -16t^2 + 18
If you use the quadratic equation, you will get 0.707 seconds.

For the second equation, you need to solve 0 = -16t^2 + 18.
If you use the quadratic equation, you will get 1.061 seconds.

No, the rate of change is not constant because this is a quadratic equation.
5 0
4 years ago
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