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We need to figure out how much string would be left, after taking away the first two pieces.
We know that the first piece is 20 inches long, so we can say that there is 52-20 inches left, or 32 inches.
The second piece is between 12 and 18 inches, meaning that there would be between 32-12 and 32-18 inches left for the third piece, or 20 and 14 inches. This means that the third piece would be at least 14 inches long, but no more than 20, since we don’t have more string than that (20+12+20=52, and 20+14+18=52)
So we can say that x is greater or equal to 14, but less than or equal to 20, or:
14<=x<=20 (“<=“ is written like a normal “<“ sign with a line _ right under it)
Find A <span>if B is between A and C.
</span><span>A.B,and C are collinear so A, B and C are line up in a line</span>
AC = AB + BC
AB=5x-19,and BC= 3x+4 given;
So
AC = 5x-19 + 3x+4
Simplify
AC = 8x -15
That would be 0.9 because 9 is in the tenths place
2.4 hours
You can get this by setting up the equation:
x/4 + x/6 = 1
Where x is equal to the amount of hours spent working. In this equation x/4 would be Doug. In 4 hours he would paint on room. x/6 would be Elaine. When you add them together using common denominators, you can find x.
