Consider the E2 elimination of 3‑bromopentane with hydroxide. The starting material consists of a chiral carbon with an in plane
bond to bromine pointing to the upper left, an in plane bond to ethyl pointing to the right, a wedged bond to ethyl pointing to the lower left and a dashed bond to hydrogen pointing to the lower left. This reacts with hydroxide to form the product, water and bromide ion. Complete the curved arrow electron-pushing mechanism and draw the structure of the organic product formed.
1 answer:
Answer:
Scheme is attached
Explanation:
When 3‑bromopentane reacts with hydroxide, (Z)-pent-2-ene will produce through E 2 (Z)-pent-2-ene.
Mechanism
Hydroxide ion (OH⁻ ) is a strong nucleophile so it abstract the proton from carbon next to the carbon attached with bromine.
The the carbon next to carbon of bromine gets -ve charge, mean while it shares its electrons with the carbon having bromine and make a double bond.
As bromine is a good leaving group so it easily gets detached from carbon, so that carbon comes to its normal state.
As a result (Z)-pent-2-ene will produce. we call it Z because mostly trans products will form.
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The given question is incomplete. The complete question is :
Which of the following Group 17 elements is the least reactive
a) Flourine
b) Chlorine
c) Astatine
d) Iodine
Answer: c) Astatine
Explanation:
Halogen is the name given to Group 17 family with general electronic configuration of which have 7 valence electrons and thus easily gain one electron to attain stable configuration.
As we move down the group from flourine to chlorine to bromine to iodine to astatine , the valence shell moves farther from nucleus and thus tendency to accept the electron decreases and thus reactivity also decreases.
Thus Astatine is the least reactive of all.