Answer:
Explanation:
1)
H₂SO₄:
Element (symbol) No of atoms in No of compounds Total atoms
1 molecule coefficient
H 2 1 2
S 1 1
O 4 4
2)
2H₃PO₄:
Element (symbol) No of atoms in No of compounds Total atoms
1 molecule coefficient
H 3 2 6
P 1 2
O 4 8
There are two mole of H₃PO₄. One mole contain 3 hydrogen atom, 1 phosphorus atom and 4 oxygen atoms. Thus in two mole of compound 6 hydrogen atoms, 2 phosphorus atom and 8 oxygen atoms are present.
E=hc/λ =6.626×10^-34×3 ×10^8 / 3×10^7 × 10^-9 = 6.626×10 ^-24J.
Answer: A, 1.3*1020, 1326
A. 1326
B. 2960.9
C. 9804
D. 8559.6
I Believe the answer to your question is C.Protista and D.Animalia and B.Eubacteria
Answer:
<u>20.25 mL.</u>
Explanation:
The volume of base required for the titration can be derived by removing the base titrant volume from the volume at endpoint.
i.e Final volume - initial volume
= (22.08 - 1.83)mL
<u>= 20.25 mL.</u>
<em>(Repeat and average volume results for accuracy.)</em>
