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3 years ago

I neeed help please help

Chemistry

2 answers:

Zina [86]3 years ago

8 0

To increase the rate of a reaction, you can increase the amount of surface area (so the third option).

By increasing the surface area, more particles become exposed and therefore it's more likely for there to be a higher rate of collisions between the reactant and the particles. Due to this, the rate of the reaction increases.

mina [271]3 years ago

7 0

A. Lowering the temperature.

I hope this helped!

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$\chi_{O_2}=\frac{0.8905 bar}{34680 bar}=2.56\times 10^{-5}$

Let the number of moles of $O_2$ gas in 1 liter water be n.

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Moles of water in 1 L $n_w=\frac{1000 g}{18 g/mol}=55.55 mol$

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$2.56\times 10^{-5}=\frac{n}{n+55.55}$

$n=1.43\times 10^{-7} moles$

$Molarity=\frac{\text{Moles of}O_2}{Volume}$

Molar concentration of oxygen gas in 1 L of water:

$=\frac{1.43\times 10^{-7} moles}{1 L}=1.43\times 10^{-7} mol/L$

The molar concentration of oxygen gas in water is $1.43\times 10^{-7} mol/L$ .

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Explanation:

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