Answer:
b. 7.5 x 10^-3
Explanation:
To solve this problem we need to keep in mind the <em>definition of molarity</em>:
- Molarity = moles of solute / liters of solution
With the above information in mind it is possible to calculate the moles of solute, given the volume (10 mL) and concentration (0.75 M) of the solution:
- First we<u> convert 10 mL to L</u> ⇒ 10 mL / 1000 = 0.01 L
Then we <u>calculate the moles of AgNO₃</u>:
- moles of solute = Molarity * Liters of solution
- 0.01 L * 0.75 M = 7.5x10⁻³ mol AgNO₃
<em>One mole of AgNO₃ contains one mole of Ag⁺</em>, thus the number of Ag⁺ moles is also 7.5x10⁻³.
Initial pressure of the gas = 65.3 kPa
Initial volume of the gas = 654 cm³
Initial temperature of the gas = 6⁰C = 273 + 6 = 279 K
Final pressure of the gas = 108.7 kPa
Final temperature of the gas = 4⁰C = 273 + 4 = 277 K
Using the combined gas law for ideal gases:
P₁V₁/T₁ = P₂V₂/T₂
where P₁, V₁ and T₁ are the pressure, volume and temperature for the initial state and P₂, V₂ and T₂ are the pressure, volume and temperature for the final state.
Plugging the given data into the combined gas law we have,
(65.3 kPa x 654 cm³) / (279 K) = (108.7 kPa x V₂)/(277 K)
V₂ = (65.3 kPa x 654 cm³ x 277 K) / (279 K x 108.7 kPa)
V₂ = 390.1 cm³
Group 6 elements usually have extra electrons to make give them an octet. So, they have 6 electrons to start and when they have an octet, they have 8.
We can find the charge by doing simple math 6 - 8 = -2
Answer is D)
Answer:
We can see the bright matter, like stars, but we know some other matter is there(dark matter)because of how it pulls on the bright matter.
Explanation:
