Answer:
maximum point
Step-by-step explanation:
Answer:
y-1=2(x+4) or y=2x+9
Step-by-step explanation:
y - 3 = 2(x + 7)
y=mx+b
m=2
(x1,y1) -> (-4, 1)
(y−y1)=m(x−x1)
plug in
y-1=2(x+4)
y-1=2x+8
y=2x+9
test:
(1)=2(-4)+9
1=-8+9
1=1
Answer:
Step-by-step explanation:
Given:
x = 2cost,
t = (1/2)arccosx
y = 2sint
dy/dx = dy/dt . dt/dx
dy/dt = 2cost
dt/dx = -1/√(1 - x²)
dy/dx = -2cost/√(1 - x²)
Differentiate again to obtain d²y/dx²
d²y/dx² = 2sint/√(1 - x²) - 2xcost/(1 - x²)^(-3/2)
At t = π/4, we have
(√2)/√(1 - x²) - (√2)x(1 - x²)^(3/2)
