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GuDViN [60]
3 years ago
7

Which of the following was not a contribution by Niels Bohr? Quantum energy emissions. The charge of an electron. There is a rel

ationship between the outer shell and chemical properties. Electrons are in orbits.
Chemistry
1 answer:
borishaifa [10]3 years ago
6 0

Out of the given options, the charge of an electron was not contributed by Neils Bohr.

Answer: Option 2

<u>Explanation: </u>

The electron's charge was determined by using oil drop experiments performed by Millikan. While Neil Bohr suggested that electrons are rotating in discrete energy levels termed as orbits.

The hydrogen model of Neil Bohr dealt with the quantum energy emission when electron excite from higher energy level to lower energy level. He also stated that there is a relationship between the outer shell and the chemical properties of elements.

So, the second option that is the charge of an electron is not contributed by Bohr as it was contributed by Millikan.

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How many moles of hydrogen molecules (h2) would be required to produce two moles of hydrogen peroxide (h2o2)?
SashulF [63]
Their should be two molecules of hydrogen (h2) to produce 2 moles of h2O2
3 0
4 years ago
A 34.0 gram sample of an un-known hydrocarbon is burned in excess oxygen to form 93.5 grams of carbon dioxide and 76.5 grams of
natka813 [3]

Answer:

The answer to your question is  CH₄

Explanation:

Process

1.- Write the possible chemical reaction

                   CxHy + O₂   ⇒    CO₂  +   H₂O

2.- Calculate the amount of carbon in the reaction

Molecular mass of CO₂ = 12 + 32 = 44 g

                         44 g of CO₂ ------------------- 12 g of carbon

                         93.5 g of CO₂ ----------------  x

                          x = (93.5 x 12) / 44

                          x = 25.5 g of carbon

3.- Calculate the mass of hydrogen in the sample

Molecular mass of water = 2 + 16 = 18 g

                         18 g of water -------------   2 g of hydrogen

                          76.5 g of water --------    x g of hydrogen

                           x = (76.5 x 2) / 18

                           x = 8.5 g of hydrogen

4.- Calculate the moles of carbon and hydrogen in the sample

                           12g of carbon ------------- 1 mol

                           25.5g of carbon ---------- x

                             x = (25.5 x 1) / 12

                              x = 2.12 moles of carbon

                            1 g of hydrogen ----------- 1 mol

                            8.5 g of hydrogen -------- x

                             x = (8.5 x 1) / 1

                             x = 8.5 moles of hydrogen

5.- Divide both number of moles by the lowest number

carbon = 2.12 / 2.12 = 1

hydrogen = 2.12 = 8,5 / 2.12 = 4

6.- Write the molecular formula

                                                    CH₄                                        

7 0
3 years ago
Read 2 more answers
How many molecules are in 3.94g of SO2?
IRISSAK [1]
To find the number of molecules, you need to first convert the mass into number of mol using the molar mass of SO2, simply add the atomic masses of each element and the number of times each element appears in the formula from the periodic table.

Then divide the mass by that value and then use Avogadro’s number to find the molecules.

Multiply by 6.02 x 10^23 Molecules.
5 0
4 years ago
Plz help i need the answer ASAP If 6.20 cm3 of a 6.75 M (M = mol/dm3) solution are diluted to 85.6 cm3 with water, what is the c
Brilliant_brown [7]

Answer:

Option A. 6.75 (6.20/85.6)

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 6.2cm³

Initial concentration (C1) = 6.75M

Final volume (V2) = 85.6cm³

Final concentration (C2) =.?

The final concentration can be obtained by using the dilution formula as show below:

C1V1 = C2V2

6.75 x 6.2 = C2 x 85.6

Divide both side by 85.6

C2 = (6.75 x 6.2) /85.6

C2 = 6.75 (6.2 / 85.6).

6 0
3 years ago
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