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3 years ago

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At STP (101.3 kPa, 0 degrees Celsius)one mole of Ar gas was collected and was found to occupy a volume of 22.4 L. What is the va

lue of the gas constant in L*kPa/mol*K?

1 answer:

valkas [14]3 years ago

7 0

Answer:

$R_{u} = 8.307\,\frac{kPa\cdot L}{mol\cdot K}$

Explanation:

Let assume that Argon behaves ideally. The equation of state for an ideal state is:

$P\cdot V = n \cdot R_{u}\cdot T$

The gas constant is:

$R_{u} = \frac{P\cdot V}{n\cdot T}$

$R_{u} = \frac{(101.3\,kPa)\cdot (22.4\,L)}{(1\,mol)\cdot (273.15\,K)}$

$R_{u} = 8.307\,\frac{kPa\cdot L}{mol\cdot K}$

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Let us first convert years to minute.

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3 years ago

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Delicious77 [7]

Answer:

$Q\approx6.4~kJ$

Explanation:

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$Q_1=m.C_s.\Delta T$

here;

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change in temperature, $\Delta T=(5-0)=5^{o}C$

$Q_1=10\times2.09\times 5$

$Q_1=104.5~J$

Amount of heat required to melt the ice at 0°C:

$Q_2=m.\Delta H_{fus}$

where, $\Delta H_{fus}=6020~J/mol$

we know that no. of moles is = (wt. in gram) $\div$ (molecular mass)

$Q_2=\frac{10}{18} \times 6020$

$Q_2=3344.44~J$

Now, the heat required to bring the water to 70°C from 0°C:

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$Q_3=10\times 4.18\times 70$

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Therefore the total heat required to warm 10.0 grams of ice at -5.0°C to a temperature of 70.0°C:

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$Q=104.5+3344.44+2926$

$Q=6374.94~J$

$Q\approx6.4~kJ$

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pickupchik [31]

Answer:

The order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

Explanation:

The rate of a chemical reaction is the number of moles of reactants consumed per unit time or the number of moles of products formed per unit. the rate of a chemical reaction is affected by the concentration of reactants

The relationship between the rate of a chemical reaction and the concentration of its reactants is given by the rate law or equation.

Generally, the rate equation is given as;

Rate = k[A]ᵃ[B]ᵇ..., where k = rate constant which is independent of concentration of the reactants, [A] = concentration of reactant A, a = order of reaction A, [B] = concentration of reaction B, b = order of reaction B.

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9 = k[A]3ˣ

3² = k[A]3ˣ

Since rate is proportional to concentration, therefore, the order of reaction, x = 2

For R1; rate = 1, Concentration = 3[A]

1 = k[A]3ˣ

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Since rate is proportional to concentration, therefore, the order of reaction, x = 0

Therefore, the order of reaction is as follows, R1 = 1; R2 = 2; R3 = 0

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Answer:

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