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mixas84 [53]
2 years ago
15

A 34.0 gram sample of an un-known hydrocarbon is burned in excess oxygen to form 93.5 grams of carbon dioxide and 76.5 grams of

water. What is a possible molecular formula of the hydro-carbon?
Chemistry
2 answers:
Tatiana [17]2 years ago
8 0

Answer:

CH_4

Explanation:

Given that:-

Mass of carbon dioxide obtained = 93.5 grams

Molar mass of carbon dioxide = 44.01 g/mol

Moles of CO_2 = 93.5 g  /44.01 g/mol = 2.12451 moles

1 mole of carbon atoms are present in 1 mole of carbon dioxide. So,

Moles of C = 2.12451 moles

Molar mass of C atom = 12.0107 g/mol

Mass of C in molecule = 2.12451 x 12.0107 = 25.51685 g

Given that the compound is a hydrocarbon which only contains hydrogen and carbon. So,

Mass of H in the sample = Total mass - Mass of C

Mass of the sample = 34.0 g

Mass of H in sample = 34.0 - 25.51685 g = 8.48315 g  

Molar mass of H = 1.0078 g/mol

Moles of H  = 8.48315 / 1.0078  = 8.41749 moles

Taking the simplest ratio for H and C as:

8.41749 : 2.12451  = 4 : 1

The possible molecular formula of the hydrocarbon formula is = CH_4

natka813 [3]2 years ago
7 0

Answer:

The answer to your question is  CH₄

Explanation:

Process

1.- Write the possible chemical reaction

                   CxHy + O₂   ⇒    CO₂  +   H₂O

2.- Calculate the amount of carbon in the reaction

Molecular mass of CO₂ = 12 + 32 = 44 g

                         44 g of CO₂ ------------------- 12 g of carbon

                         93.5 g of CO₂ ----------------  x

                          x = (93.5 x 12) / 44

                          x = 25.5 g of carbon

3.- Calculate the mass of hydrogen in the sample

Molecular mass of water = 2 + 16 = 18 g

                         18 g of water -------------   2 g of hydrogen

                          76.5 g of water --------    x g of hydrogen

                           x = (76.5 x 2) / 18

                           x = 8.5 g of hydrogen

4.- Calculate the moles of carbon and hydrogen in the sample

                           12g of carbon ------------- 1 mol

                           25.5g of carbon ---------- x

                             x = (25.5 x 1) / 12

                              x = 2.12 moles of carbon

                            1 g of hydrogen ----------- 1 mol

                            8.5 g of hydrogen -------- x

                             x = (8.5 x 1) / 1

                             x = 8.5 moles of hydrogen

5.- Divide both number of moles by the lowest number

carbon = 2.12 / 2.12 = 1

hydrogen = 2.12 = 8,5 / 2.12 = 4

6.- Write the molecular formula

                                                    CH₄                                        

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Kobotan [32]
First, you need to convert kg to g. 
So, 1 kg =1000g.
3.5 x 1000 = 3500g Ca(OH)2

We need to know the molar mass of Ca(OH)2. 
Ca= 40.08 g
O=2(15.999)
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Add them all together and you get 74.0938 g.

Put it in the formula from mass to moles. 

# of moles = grams Ca(OH)2 x 1 mol Ca(OH)2
                                                  --------------------
                                                  molar mass Ca(OH)2

3500 g Ca(OH)2 x 1 mol Ca(OH)2
                              ---------------------
                             74.0938 g Ca(OH)2

So divide 1/74.0938 and multiply by 3500.

You will get about 47.24 moles Ca(OH)2.

Hope this helps! :)
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List the following elements in order , from best to worst conductor of electric current : silicon , copper, iodine.
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Determine the quantity of bromine atoms in 18.0g of HgBr2 (using factor label method)
Gnoma [55]

Considering the definition of molar mass and Avogadro's Number, the quantity of bromine atoms in 18.0g of HgBr₂ is 6.023×10²² atoms.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

<h3>Molar mass of HgBr₂</h3>

In this case, you know the molar mass of the elements is:

  • Hg= 200 g/mole
  • Br= 79.9 g/mole

So, the molar mass of the compound HgBr₂ is calculated as:

HgBr₂= 200 g/mole + 2×79.9 g/mole

Solving:

HgBr₂= 359.98 g/mole

Definition of Avogadro's Number

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Quantity of bromine atoms in 18.0g of HgBr₂</h3>

Factor-label describes a technique to convert one quantity to another quantity. This method uses the fact that any number or expression can be multiplied by one without changing its value; this is, consists in multiply the value you are given, unit of measurement included, by the conversion factor in fraction form.

Finally, knowing that 2 moles of Br are present in 1 mole of HgBr₂, and considering the molar mass of HgBr₂ and the definition on Avogadro's number, the quantity of bromine atoms in 18.0g of HgBr₂ is calculated as:

18 gr HgBr_{2}\frac{1 mole HgBr_{2}}{359.98 gHgBr_{2}} \frac{2 mole Br}{1 mole HgBr_{2} } \frac{6.023x10^{23}atoms Br }{1 mole Br} =6.023x10^{22}atoms

In summary, the quantity of bromine atoms in 18.0g of HgBr₂ is 6.023×10²² atoms.

Learn more about

molar mass:

<u>brainly.com/question/5216907</u>

<u>brainly.com/question/11209783</u>

<u>brainly.com/question/7132033</u>

<u>brainly.com/question/17249726</u>

Avogadro's Number:

<u>brainly.com/question/11907018</u>

<u>brainly.com/question/1445383</u>

<u>brainly.com/question/1528951</u>

8 0
2 years ago
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