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4 years ago

As carbon dioxide sublimes, its entropy (1) decreases (2) increases (3) remains the same

Chemistry

2 answers:

Fed [463]4 years ago

8 0

Answer: (2) increases

Explanation: Entropy is the measure of randomness or disorder of a system. More is the random arrangement of molecules in a system , more is the entropy of the system. More ordered is the arrangement of molecules in a system, less is the entropy of the system.

When carbon dioxide sublimes, it means solid carbon dioxide is directly changing to gaseous state without undergoing into liquid state, thus the molecules will be more random and thus the entropy will increase.

Papessa [141]4 years ago

5 0

When something sublimes (Goes straight from solid to gas), it takes in energy, as it is an endothermic process, so its entropy increases

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at atmoshperic pressure, a balloon contains 2.00L of nitrogen of gas. How would the volume change if the Kelvin temperature were

Nataly [62]

<u>Answer:</u> The percent change in volume will be 25 %

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=2L\\T_1=T_1\\V_2=?\\T_2=75\% \text{ of }T_1=0.75\times T_1$

Putting values in above equation, we get:

$\frac{2L}{T_1}=\frac{V_2}{0.75\times T_1}\\\\V_2=\frac{2\times 0.75\times T_1}{T_1}=1.5L$

Percent change of volume = $\frac{\text{Change in volume}}{\text{Initial volume}}\times 100$

Percent change of volume = $\frac{(2-1.5)}{2}\times 100=25\%$

Hence, the percent change in volume will be 25 %

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3 years ago

You have a spot of oil, which is nonpolar, on your favorite shirt. in which substance will the oil be most likely dissolve?

Natalija [7]

In concentrated soap solution.

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4 years ago

Read 2 more answers

Which of the following conditions most favors the process of dissolution?

Inga [223]

What following?? Conditions??

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3 years ago

If I have 340 mL of a 0.5 M NaBr solution, what will the concentration be if I add

Charra [1.4K]

Answer:

Option C. 0.23 molar

Explanation:

The following data were obtained from the question given:

C1 = 0.5 M

V1 = 340mL

V2 = since 400mL was added to the original volume, therefore = 340 + 400 = 740mL

C2 =?

The concentration of the diluted solution can be calculated by using the following:

C1V1 = C2V2

0.5 x 340 = C2 x 740

Divide both side by 740

C2 = (0.5 x 340) / 740

C2 = 0.23M

Therefore, the new concentration of the solution is 0.23M

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3 years ago

What is the volume of 2 moles of He at STP?

larisa86 [58]

Answer:

STP conditions imply a temperature of 273.15 K and a pressure of 100 kPa. When tose conditions are met, 1 mole of any ideal gas will have a volume of 22.7 L. So, if 1 mole occupies a volume of 22.7 L, 2 moles will occupy a volume twice as big. Likewise, 0.5 moles will occupy half the volume 1 mole occupies. Assuming that the gas is at standard temperature and pressure (STP), one mole of any gas occupies 22.4 L . This means the number of moles of O2 is 222.4=0.089 mol .

Explanation:

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3 years ago