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2 years ago

Balance the equation Ca(s) + H3PO4(aq) ---->Ca3(PO4)2(s) + H2(g)

Chemistry

1 answer:

vovikov84 [41]2 years ago

3 0

Answer: CO2x+O4H I don’t know if this is the right answer

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A solution is prepared by combining 5.00 mL of 4.8x10-4 M NaSCN solution, 2.00 mL of 0.21 M Fe(NO3)3 solution and 13.00 mL of 0.

Tcecarenko [31]

Answer:

The analytical concentrations of thiocyanate ions:

$[SCN^-]=0.00012 mol/L$

The analytical concentrations of ferric ions:

$[Fe^{3+}]=0.063 mol/L$

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

1) Moles of sodium thiocyanate = n

Volume of sodium thiocyanate solution = 5.00 mL = 0.005 L

(1 mL = 0.001L)

Molarity of the sodium thiocyanate = $4.8\times 10^{-4} M$

$n=4.8\times 10^{-4} M\times 0.005 L=2.4\times 10^{-6}mol$

1 mole of sodium thiocyanate has 1 mol of thiocyante ions.

So, moles of thioscyanate ions in $2.4\times 10^{-6}mol$ of NaSCN.

$=1\times 2.4\times 10^{-6}mol=2.4\times 10^{-6}mol$

2) Moles of ferric nitrate = n'

Volume of ferric nitrate solution = 2.00 mL = 0.002 L

Molarity of the ferric nitrate = 0.21 M

$n'=0.002 M\times 0.21 L=0.00042 mol$

1 mole of ferric nitrate has 3 moles of ferric ions.

So number of moles of ferric ions in 0.00042 moles of ferric nitrate is :

$3\times 0.00042 mol=0.00126 mol$

Volume of nitric acid = 13.00 mL

Total volume by adding all three volumes of solutions = V

V = 5.00 mL + 2.00 mL + 13.00 mL = 20.00 mL = 0.020 L

The analytical concentrations of thiocyanate ions:

$[SCN^-]=\frac{2.4\times 10^{-6}mol}{0.020 L}=0.00012 mol/L$

The analytical concentrations of ferric ions:

$[Fe^{3+}]=\frac{0.00126 mol}{0.020 L}=0.063 mol/L$

3 0

3 years ago

Read 2 more answers

A solid piece of lead has a mass of 23.94g and a volume of 2.10cm^3. from these data, calculate the density of lead in si units

jeyben [28]

A density of a substance is constant. It is an extensive property, meaning it does not depend on the amount of substance because it is a ratio of mass to volume. No matter how much of each there is, they would always have a fixed ratio called density. For lead, the density is

Density = mass/volume
Density = 23.94 g/ 2.10 cm³
Density = 11.4 g/cm³

4 0

3 years ago

How many moles of NaOH are there in 3 mL of 9.0M NaOH?

Mademuasel [1]

Answer:

0.027mol

Explanation:

9M NaOH tells us that there is 9 mol of NaOH per L of NaOH

converting 3mL to L = 0.003L

0.003L * 9 mol/L = 0.027mol

5 0

3 years ago

Four facts about kinetic theory

Arlecino [84]

An object keeps the same amount of kinetic energy unless it speeds up or slows down.

Kinetic energy can be calculated for any moving object as long as the objects' mass and speed are known.

The unit used when measuring kinetic energy is called a joule.

Kinetic energy can occur in any direction whether up and down or left to right.

5 0

3 years ago

Consider X + Z -> ?

Licemer1 [7]

Answer:

Explanation:

Element Z acquires two electrons from element X for stability

4 0

3 years ago