Question

The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and length of this rectangle?

Answer 1

The width of rectangle is $2\frac{1}{4}\ cm$ and length is $5\frac{5}{12}\ cm$

Step-by-step explanation:

Let,

Width of rectangle = w

Length of rectangle = w+$3\frac{1}{6}=w+\frac{19}{6}$

Perimeter of rectangle = $15\frac{1}{3}=\frac{46}{3}\ cm$

Perimeter of rectangle = 2(Length + Width)

$2(w+\frac{19}{6}+w)=\frac{46}{3}\\2(2w+\frac{19}{6})=\frac{46}{3}\\4w+\frac{19}{3}=\frac{46}{3}$

Subtracting $\frac{19}{3}$ from both sides

$4w+\frac{19}{3}-\frac{19}{3}=\frac{46}{3}-\frac{19}{3}\\4w=\frac{46-19}{3}\\4w=\frac{27}{3}\\4w=9$

Dividing both sides by 4

$\frac{4w}{4}=\frac{9}{4}\\w=\frac{9}{4}$

Therefore,

Width of rectangle = w = $\frac{9}{4}=2\frac{1}{4}$ cm

Length of rectangle = $w+\frac{19}{6}=\frac{9}{4}+\frac{19}{6}=\frac{27+38}{12}=\frac{65}{12}=5\frac{5}{12}\ cm$

The width of rectangle is $2\frac{1}{4}\ cm$ and length is $5\frac{5}{12}\ cm$

Keywords: perimeter, addition

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