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Viefleur [7K]
3 years ago
13

The ability to perceive others' emotions can be attributed to which of the following parts of the brain?

Chemistry
1 answer:
Marina86 [1]3 years ago
5 0
It is a                                                                                                                                               .......................................................................                                   
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Use the balanced equation below to answer the question that follows
natta225 [31]
It’s c hdjdkdmnfvdheidk
4 0
3 years ago
What is the change in energy of a gas at a pressure of 105 kPa, if 245 J of energy is added causing a change in volume from 25.3
Ahat [919]

Answer:

-1151.5 J

Explanation:

Given that:

The supplies energy = 245 L

The energy used in the expansion of gas = Pressure ×ΔV (change in volume)

At standard conditions;

Pressure = 105 × 10³ Pa

energy used in the expansion = 105 × 10³ Pa × (38.6 - 25.3)L

= 1396.5 J

Thus, the change in the energy of gas = 245 - 1396.5 J

= -1151.5 J

Hence, we can conclude that the gas has lost its own energy in the process of expansion.

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3 years ago
Sasha from aot died :(
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8 0
3 years ago
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Both of calciums electrons are in its innermost shell. Explain why.
zimovet [89]

The atomic number of calcium is 20 which means it has 20 protons and as an atom (not an ion) it also has 20 electrons. These are in four energy levels (1 though 4) .


6 0
3 years ago
A gas occupies 50.0mL at a standard temp. What volume would it occupy at 335 Celsius with
tino4ka555 [31]

Answer:

V₂ = 111.3 mL

Explanation:

Given data:

Initial volume of gas = 50.0 mL

Initial temperature = standard = 273.15 K

Final volume = ?

Final temperature = 335 °C (335+273.15 = 608.15 K)

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 50.0  mL ×608.15 K / 273.15 k

V₂ = 30407.5 mL.K / 273.15 K

V₂ = 111.3 mL

7 0
3 years ago
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