<u>Question 1</u>
The formula mass of methanol is
g/mol.
Therefore, in 5.0 grams of methanol, there are
moles.
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<u>Question 2</u>
The formula mass of copper(II) carbonate is
g/mol.
This means that in 9.0 grams of copper(II) carbonate, there are
moles.
Using Avogradro's number, there are
molecules.
<u>Question 3</u>
The formula mass of cyclohexane is
g/mol.
So, 3.0 grams of cyclohexane is the same as
moles.
<u>Question 4</u>
The formula mass of benzene is
g/mol.
This means that 4.00 moles of benzene has a mass of
grams.
<u>Question 5</u>
1000 atoms of calcium is the same as
moles.
This is equal to
grams.
Answer:
Physical and chemical changes are similar because they are both caused by the interaction of two or more particles.
Explanation:
Physical and chemical changes are similar because they are both caused by the interaction of two or more particles. Physical changes occur through vibrations, impacts, and other forms of movement. Chemical changes are caused by the interaction of two or more atoms or molecules.
Answer:
131 atm
Explanation:
To find the new pressure, you need to use Boyle's Law:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.
P₁ = 3.88 atm P₂ = ? atm
V₁ = 7.74 L V₂ = 0.23 L
P₁V₁ = P₂V₂ <----- Boyle's Law
(3.88 atm)(7.74 L) = P₂(0.23 L) <----- Insert values
30.0312 = P₂(0.23 L) <----- Simplify left side
131 = P₂ <----- Divide both sides by 0.23
Answer:
Kc = 8.05x10⁻³
Explanation:
This is the equilibrium:
2NH₃(g) ⇄ N₂(g) + 3H₂(g)
Initially 0.0733
React 0.0733α α/2 3/2α
Eq 0.0733 - 0.0733α α/2 0.103
We introduced 0.0733 moles of ammonia, initially. So in the reaction "α" amount react, as the ratio is 2:1, and 2:3, we can know the moles that formed products.
Now we were told that in equilibrum we have a [H₂] of 0.103, so this data can help us to calculate α.
3/2α = 0.103
α = 0.103 . 2/3 ⇒ 0.0686
So, concentration in equilibrium are
NH₃ = 0.0733 - 0.0733 . 0.0686 = 0.0682
N₂ = 0.0686/2 = 0.0343
So this moles, are in a volume of 1L, so they are molar concentrations.
Let's make Kc expression:
Kc= [N₂] . [H₂]³ / [NH₃]²
Kc = 0.0343 . 0.103³ / 0.0682² = 8.05x10⁻³